在 R 中，取一个日期字符串并将其转换为日期时间格式（使用 lubridate）

Question

In RI am trying to take a date string and convert it to date time format using lubridate but anm getting an error that:

All formats failed to parse. No formats found. 

Using this code:

lubridate::as_date("1/2/34")

Shouldn't this just return a formated date time?

Answer 1

as.Date or as_Date needs format . By default, it can parse if the format is %Y-%m-%d . Here, it is not the case. So

lubridate::as_date("1/2/34", format ="%d/%m/%y")

Or more compactly

lubridate::dmy("1/2/34")

Based on the string, it is not clear whether it is day/month/year or month/day/year. Also, for 2-digit year, there is an issue with prefix ie it can be either "19" or "20". Here, it would parse at "2034"