如何在r中重复数据帧的顺序

Question

I want to do same order as removing the first rows for several dataframes.

lab1 <- lab1[-c(1),]
lab2 <- lab2[-c(1),]
lab3 <- lab3[-c(1),]
lab4 <- lab4[-c(1),]
lab5 <- lab5[-c(1),]
lab6 <- lab6[-c(1),]
lab7 <- lab7[-c(1),]
lab8 <- lab8[-c(1),]
lab9 <- lab9[-c(1),]
lab10 <- lab10[-c(1),]
...

I want to use repeated phase like this.

for(i in 2:19){ labi <- labi[-c(1),]}

However, labi is recognized as a dataframe name. I need to do such orders for many dataframes. Can someone help?

Answer 1

How do you create the dataframes? Is it possible instead to make a list of lab[[i]] ?

Else, you can write the expression as a string then evaluate it, but it's a bit of a hacky way, it would be better to avoid it:

cmd <- paste0("lab", 1, "[c(-1),]")
eval(str2expression(cmd))

Answer 2

Thank you! I make dataframes from excel files.

lab1 <- readxl::read_excel(path="001.xlsx", sheet="sheet1", col_names=FALSE)
lab2 <- readxl::read_excel(path="002.xlsx", sheet="sheet1", col_names=FALSE)

I have an error for making lab[[1]] . I think I need an emtpy dataframe. Each file has different number of rows. But, same name of columns. How can I make the dataframe for this case?

Answer 3

Maybe you can try list2env like below

list2env(
  lapply(mget(ls(pattern = "lab\\d+")), function(x) x[-1, ]),
  envir = .GlobalEnv
)