如何在bash shell脚本中打印条件语句

Question

I am trying to add the below conditional statement of mine which converts one GMT offset date string column into MST .

Sample input

07/Sep/2020:11:28:01 +0000!@44.20.20.1!@TestDevice

Sample output

07/Sep/2020:04:28:01 -7000!@44.20.20.1!@TestDevice

This conditional statement works fine

STR='07/Sep/2020:11:28:01 +0000'; SUB='+000'; if [[ "$STR" == *"$SUB"* ]]; then STR="${STR//\// }"; STR="${STR/:/ }"; TZ="MST" date --date="$STR" +'%d/%h/%Y:%H:%M:%S %z'; else echo "$STR"; fi

I want to place the above conditional logic while extracting data from a file called output.csv with delimiter as "!@" and dump to output2.csv.So i need to put the above conditional logic in place of $1 in below statement

awk -F "\!@" '{print $1"\!@"substr($2,1,200)"\!@"$3}' output.csv >output2.csv

So I am trying it like this but it isnt working

STR=$1
awk -F "\!@" '{print $STR='07/Sep/2020:11:28:01 +0000'; SUB='+000'; if [[ "$STR" == *"$SUB"* ]]; then STR="${STR//\// }"; STR="${STR/:/ }"; TZ="MST" date --date="$STR" +'%d/%h/%Y:%H:%M:%S %z'; else echo "$STR"; fi"\!@"substr($2,1,200)"\!@"$3}' output.csv >output2.csv

Can someone please help

Answer 1

awk -F '!@' -v OFS='!@' '$1~/[0-9A-Za-z /:+-]/{gsub("/"," ",$1);sub(":"," ",$1);"TZ=MST date --date=\""$1"\" +\"%d/%h/%Y:%H:%M:%S %z\""|getline d;print d,substr($2,1,200),$3}' output.csv >output2.csv

这有效。谢谢 jhnc