[英]SQL DB2: Need latest records until column value changes
Need to select all recent records belonging to a client having a unique value in column ANDRI (value = P) until value in column ANDRI changes (value = Q).需要选择属于在 ANDRI 列中具有唯一值(值 = P)的客户的所有最近记录,直到 ANDRI 列中的值发生变化(值 = Q)。 The records need to be grouped based on client name ID (unique ID) which is present in Table B. Two tables can be joined by column ID which is a PRIMARY KEY.记录需要根据表 B 中存在的客户端名称 ID(唯一 ID)进行分组。两个表可以通过作为主键的列 ID 连接。
Here is my DB2 Table A:这是我的 DB2 表 A:
+---------+---------------+------+-----+---------+-------+
| ID | Client Type | ANDRI| Date (Timestamp) |
+---------+---------------+------+-----+---------+-------+
| 878 | Personal | P | 2020-09-22 16:47:08 |
| 576 | Personal | P | 2020-09-22 10:47:08 |
| 745 | Personal | P | 2019-05-21 14:47:08 |
| 142 | Business | Q | 2019-09-20 16:11:08 |
| 711 | Personal | Q | 2018-02-12 15:27:08 |
| 441 | Personal | P | 2018-01-29 10:57:08 |
| 371 | Personal | P | 2017-05-20 11:17:08 |
| 115 | Personal | P | 2016-10-12 14:47:08 |
+---------+---------------+------+-----+---------+-------+
Here is my DB2 Table B:这是我的 DB2 表 B:
+---------+---------------+------+-----+---------+-------+
| ID | Client Name ID| ODER| Date (Timestamp) |
+---------+---------------+------+-----+---------+-------+
| 878 | Alice | A | 2020-09-22 16:47:08 |
| 576 | Alice | A | 2020-09-22 10:47:08 |
| 745 | Alice | A | 2019-05-21 14:47:08 |
| 142 | Sandra | B | 2019-09-20 16:11:08 |
| 711 | Alice | B | 2018-02-12 15:27:08 |
| 441 | Alice | A | 2018-01-29 10:57:08 |
| 371 | Sandra | A | 2017-05-20 11:17:08 |
| 115 | Sandra | A | 2016-10-12 14:47:08 |
+---------+---------------+------+-----+---------+-------+
I expect below output:我期望以下输出:
| ID | Client Name ID| Date (Timestamp) |
+---------+---------------+------+-----+---------+
| 878 | Alice | 2020-09-22 16:47:08 |
| 576 | Alice | 2020-09-22 10:47:08 |
| 745 | Alice | 2019-05-21 14:47:08 |
If possible, it would be helpful if we can use ROW_NUMBER() function in SQL.如果可能的话,如果我们可以在 SQL 中使用 ROW_NUMBER() 函数会很有帮助。
My SQL which I have been using (but it needs some tweaking):我一直在使用的 SQL(但需要一些调整):
SELECT T.*
FROM TABLEB T
JOIN
(
SELECT Client Name ID
FROM (
SELECT Date, Client Name ID
, ROWNUMBER() OVER (PARTITION BY Client Name ID
ORDER BY Date DESC) RN
FROM TABLEB
)
WHERE RN IN (1, 2)
GROUP BY Client Name ID
HAVING MIN(ODER) = MAX(ODER) AND COUNT(1) = 2 AND MIN(ODER) = 'A'
) G
ON G.client name ID = T.client name ID
AND T.ID IN (SELECT ID FROM TABLEA WHERE ANDRI = 'P')
ORDER BY T.Client Name ID;
select b.*
from a join
b
on a.id = b.id
where a.date > (select max(a2.date)
from a a2
where a2.andri <> 'P'
);
Given that the same dates are in both tables, you may not need the join
in the outer query:鉴于同一日期两个表中,你可能不需要join
外部查询:
select b.*
from b
where b.date > (select max(a2.date)
from a a2
where a2.andri <> 'P'
);
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