生成一个 .tab 文件，文件名和路径由制表符分隔

Question

I have just started learning linux CLI. I am using snippy tool for comparing multiple files that require a .tab format file. This tab formatted file should be consisting of the paths and filenames separated by tab (\\t).

I have run this two commands separately to generate a list of filenames and paths.

find $(pwd)/*.fna > /home/fan/onas/filenames.tab

and

ls > filenames.tab

but whenever I run this command to check the tabs in file. There is no tab (\\t) exists inside the file.

cat -vet filenames.tab

I have used also this command to replace the \\n with \\t. But it doesn't work here.

sed 's/\n/\t/g' filenames.tab > file2.tab

In short, I'm trying to generate a file having filenames and paths separated by tabs or .tab format. Could somebody help me with this? Thanks

Answer 1

The command printf ...

printf "%s\t" $(ls -A $(pwd)) >files.tab

...formating output of ls -A (also hidden files) separated with tabs to ( > ) files.tab.

If your printf also supports -v then you can do...

printf -v FILES "%s\t" $(ls -A $(pwd))
echo ${FILES}

But the tabs sadly get lost. Writing it to a file like in the first example corrects it...

printf "%s\t" ${FILES} >files.tab

Wonder why only one %s\\t ? Hm, its like a foreach on an array. For each element in the whitespace separated list printf do the %s\\t and throws other whitespace away.