std::runtime_error 子项中的默认构造函数

Question

I have two exception classes that inherit from std::runtime_error. The first one, AError , works just fine.

class AError : public std::runtime_error {
public:
    const char* what() const noexcept
    {
        return "Error of type A!";
    }
};

The second one, BError , does not compile because std::runtime_error does not have a default constructor.

class BError : public std::runtime_error {
public:
    const int num_;

    BError(int n) : num_(n) {}; // ERROR: no default constructor for runtime_error

    const char* what() const noexcept
    {
        return "Error of type B!";
    }
};

It seems to me that AError should not compile because the default constructor of AError should call the default constructor of std::runtime_error in the default constructor AError . What is happening in the default constructor of AError that allows that example to compile?

Answer 1

It seems to me that AError should not compile because the default constructor of AError should call the default constructor of std::runtime_error in the default constructor AError.

The default ctor of AError is deleted because it inherits from a class that has no default ctor. try the following and the code won't compile

AError er;

Answer 2

The definition of AError compiles because it doesn't have a default constructor (one that accepts no arguments). Implicit generation of the default constructor is suppressed because std::runtime_error doesn't have one. The class definition, in itself, has no diagnosable errors, since it doesn't create any instances of the class.

There is a diagnosable error on any attempt to create an instance of AError using a default constructor

AError an_error;    // error since AError cannot be default constructed

In BError , the definition of the constructor (within class BError )

 BError(int n) : num_(n) {}; // ERROR: no default constructor for runtime_error

attempts to implicitly construct the base std::runtime_error , even though it is not listed in the initialiser list. So this definition is functionally equivalent to

BError(int n) : std::runtime_error(), num_(n) {};

and is a diagnosable error, due to the attempt - clearly visible to the compiler - to use the (non-existent) default constructor of std::runtime_error .

You can make this compile by simply using an appropriate constructor from std::runtime_error , such as

BError(int n) : std::runtime_error(""), num_(n) {};

which will call the constructor of std::runtime_error that accepts a const char * .