处理大量数据的 if else 语句以外的有效方式 [重复]

Question

i need to compare a lot of data, what i'm doing right now is using if else statement but it will cost thousands of line, is there any efficient way to do it properly ?. this is the code :

// the data will look like this
selected_data_jan = [20]
year1_jan = [30]
// the data is a sum from several lists

if selected_data_jan[0] < year1_jan[0] :
    result = selected_data_jan[0] - year1_jan[0]
    condition_decrease.append("value decrease this year" +result+ " cases")
elif selected_data_jan[0] > year1_jan[0] :
    result = selected_data_jan[0] - year1_jan[0]
    condition_increase.append("value increase this year" +result+ " cases")
    if selected_data_jan[0] > year1_jan[0] *2:
        result = selected_data_jan[0] - year1_jan[0]*2
        condition_increase.clear()
        condition_increase.append("value increased 2-fold this year, as much" +result+ "cases")
else:
    result = selected_data_jan[0] - year1_jan[0]
    condition_equal.append("value equal this year")

//after this selected_data_jan will be compared with year2 and year3
//and there will be selected_data_feb,mar,apr...des too

the selected_data_jan (monthly) and year1_jan (yearly) got the value form dataframe and turn it into a list, and the list value will be like this :

selected_data_jan_raw = [6,3,5,6]
// then ill sum the list
selected_data_jan = sum(selected_data_jan_raw)

i want to do it efficiently and fewer lines, if I did it the way I do it now it would take thousands of lines, how can i make it work the way i want ?. thanks in advance.

Answer 1

You can create something like this to repeat the process. I am not sure how your data is. I am making assumptions. Once I know what your data will look like, the solution can be tweaked.

def check_result(sel_mon, year):
    if sel_mon < year:
        diff = sel_mon - year
        cond = 'de'
        results = "value decrease this year" + str(diff)+ " cases"
    elif sel_mon > (year * 2):
        cond = 'i2'
        diff = sel_mon - (year * 2)
        results = "value increase 2-fold this year, as much" +str(diff)+ " cases"
    elif sel_mon > year:
        cond = 'i1'
        diff = sel_mon - year
        results = "value increase this year" +str(diff)+ " cases"
    else:
        cond = 'eq'
        diff = sel_mon - year
        results = "value equal this year"

    return cond, results


selected_data = [10,20,30,40,50,60,70,80,90,100,110,120]
years = [40,50,60,80]

for yrs in years:
    for mon in selected_data:
        condition, cond_result = check_result(mon,yrs)

        #for each year, you can send the selected data
        #assumption is selected data is constant for various years
        
        #now you have the type of result
        #de = decreased, i1 = increased, i2 = 2-fold increase, eq = equal
        #you also have the result string to work with