在python中仅使用一个装饰器使用定义的属性并将n个属性传递给包装器

Question

I am learning to use decorators and I can't figure out how to pass already defined attributes to the wrapper without making a function specific decorator.

Let's say I have a decorator :

def decorator(func):
    def wrapper():
        print("Before the function")
        func()
        print("After the function")

    return wrapper

With this I am only able to use it with functions with only defined attributes or without any attribute like :

@decorator
def foo1(attribute1=10, attribute2=20):
    print(attribute1, attribute2)
    return

foo1()

But it makes me unable to run :

foo1(1, 2)

With this problem, I also can't use this decorator on different functions that don't have the same amount of attributes to set.

So, it there a way to fix this problem without the use of *args and **kwargs or at least without having to call a function that would look like this : foo((arg1, arg2, argn)) ? Because it would make me unable to define any attribute. This is my only restrain.

Thanks.

Answer 1

The wrapper has to accept arguments (because it replaces the original function bound to the decorated name), and those arguments have to be passed to func .

def decorator(func):
    def wrapper():
        print("Before the function")
        func()
        print("After the function")

    return wrapper