我有两个字符串数组。 我想通过lowerCasing数组中的每个值来比较两个数组，如果匹配则返回true/false

Question

I am giving the example of two array.What is the best way to do this?Can we use some() function?

let firstArray = ['WickedWeed'];
let secondArray = ["wickedweed'];


//Output

true;

Answer 1

If there is only one element, then:

firstArray[0].toLowerCase() == secondArray[0].toLowerCase()

If there are multiple elements, then

firstArray.every((e,i)=>(secondArray[i].toLowerCase()==e.toLowerCase()))

If you don't need to match the index, then:

firstArray.map(e=>e.toLowerCase()).every(e=>secondArray.map(e=>e.toLowerCase()).includes(e))

 var firstArray=["abc","deF","zzz"]; var secondArray=["ABC","DEF","zZz"]; console.log(firstArray.map(e=>e.toLowerCase()).every(e=>secondArray.map(e=>e.toLowerCase()).includes(e)));

This can be computationally quite inefficient for long arrays, in which case it would be better to do it in two steps:

 var firstArray=["abc","deF","zzz"]; var secondArray=["ABC","DEF","zZz"]; var secondArrayl = secondArray.map(e=>e.toLowerCase()); console.log(firstArray.map(e=>e.toLowerCase()).every(e=>secondArrayl.includes(e)));

If you don't need to match every element:

 var firstArray=["abc","deF","zzz"]; var secondArray=["ABC"]; var secondArrayl = secondArray.map(e=>e.toLowerCase()); console.log(firstArray.map(e=>e.toLowerCase()).some(e=>secondArrayl.includes(e)));

Answer 2

you can use loadash docs for isequal

_.isEqual(array1, array2)