通过在python中提供条件来创建多个数据框

Question

I'm trying create multiple data frames from a single data-frame. I managed to achieve the process by repeating the same line of code, but its looks tedious and is not time friendly. I want to create a loop that iterates through the data-frame and create dataframes for me. Also I have a list of copy of my Intial dataframe(from which I want to create multiple dataframes).

df_list = [df_0run,df_1run,df_2run,df_3run,df_4run,df_5run,df_6run]

Please suggest an approach for my question.

df_0season1=df_0run.loc[df_0run['Season_Id']==1]
df_0season2=df_0run.loc[df_0run['Season_Id']==2]
df_0season3=df_0run.loc[df_0run['Season_Id']==3]
df_0season4=df_0run.loc[df_0run['Season_Id']==4]
df_0season5=df_0run.loc[df_0run['Season_Id']==5]
df_0season6=df_0run.loc[df_0run['Season_Id']==6]
df_0season7=df_0run.loc[df_0run['Season_Id']==7]
df_0season8=df_0run.loc[df_0run['Season_Id']==8]
df_0season9=df_0run.loc[df_0run['Season_Id']==9]

In this fashion I want to create multiple dataframes, and return them as a list. or multiple lists.

Required output

Seasons list = [df_0season1,df_0season2,df_0season3,df_0season4,df_0season5,df_0season6,df_0season7,df_0season8,df_0season9, 
df_1season1,df_1season2,df_1season3,df_1season4,df_1season5,df_1season6,df_1season7,df_1season8,df_1season9, 
df_2season1,df_2season2,df_2season3,df_2season4,df_2season5,df_2season6,df_2season7,df_2season8,df_2season9, 
df_3season1,df_3season2,df_3season3,df_3season4,df_3season5,df_3season6,df_3season7,df_3season8,df_3season9, 
df_4season1,df_4season2,df_4season3,df_4season4,df_4season5,df_4season6,df_4season7,df_4season8,df_4season9,
 df_5season1,df_5season2,df_5season3,df_5season4,df_5season5,df_5season6,df_5season7,df_5season8,df_5season9]

Answer 1

I think you can use a little help of exec over here,

for i in range (1,10):
    exec("""df_0season{}=df_0run.loc[df_0run['Season_Id']=={}]""".format(i))

This is just a basic application of exec and you can modify it as your requirement.