如何在XQUERY Marklogic中获取json doc的每个字段？

Question

How to get each field of json doc in XQUERY Marklogic?

let $doc :=
{
"field1" :'t',
"field2" : 'th',
"filed4": 'the'

}

return
$doc//??,
{
"New Filed" : "Added"
}

So how can we get the output like below ?

{ "field1" :'t', "field2" : 'th', "filed4": 'the' ,"New Filed" : "Added"}

Answer 1

One approach: use the xdmp:from-json() to convert the immutable JSON node to a mutable map and then set the field:

return xdmp:from-json($doc) => map:with("NewField", "Added")

For more detail, see: https://docs.marklogic.com/xdmp:from-json

Hoping that helps,

Answer 2

A JSON object is really just a specialized map. So you can use map operators, like the + union operator :

let $doc := object-node
{
"field1" :'t',
"field2" : 'th',
"filed4": 'the'
}

return 
  $doc + map:entry("NewField", "added")