简体   繁体   English

在 JAVA 中展平多维 JSON

[英]Flattening multidimensional JSON in JAVA

I have a JSON which looks like this,我有一个看起来像这样的 JSON,

{
  "users": [
    {
      "displayName": "Sharad Dutta",
      "givenName": "",
      "surname": "",
      "extension_user_type": "user",
      "identities": [
        {
          "signInType": "emailAddress",
          "issuerAssignedId": "kkr007@gmail.com"
        }
      ],
      "extension_timezone": "VET",
      "extension_locale": "en-GB",
      "extension_tenant": "EG12345"
    },   
    {
      "displayName": "Sharad Dutta",
      "givenName": "",
      "surname": "",
      "extension_user_type": "user",
      "identities": [
        {
          "signInType": "emailAddress",
          "issuerAssignedId": "kkr007@gmail.com"
        }
      ],
      "extension_timezone": "VET",
      "extension_locale": "en-GB",
      "extension_tenant": "EG12345"
    }
  ]
}

I am writing a Java code where I am parsing this Multidimensional JSON to FLAT JSON.我正在编写一个 Java 代码,我将这个多维 JSON 解析为 FLAT JSON。 If you look closely, the JSON is wrapped in a "users" wrapper and then has couple of users as objects.如果仔细观察,JSON 被包装在“用户”包装器中,然后有几个用户作为对象。 For each user, there is a field called "identifiers" which is again a wrapper.对于每个用户,都有一个称为“标识符”的字段,它也是一个包装器。

I want to flat this JSON, I have written a code but it is leaving a JSON blob for identifiers, for non nested it is working fine我想把这个 JSON 弄平,我写了一个代码,但它为标识符留下了一个 JSON blob,对于非嵌套它工作正常

JSONObject output;
        try {
            output = new JSONObject(userJsonAsString);
            JSONArray docs = output.getJSONArray("users");
            System.out.println(docs);

This is giving me below output, however i still have to flat inner wrapper "identifiers"这给了我下面的输出,但是我仍然必须平整内部包装器“标识符”

[
  {
    "extension_timezone": "VET",
    "extension_tenant": "EG12345",
    "extension_locale": "en-GB",
    "identities": [
      {
        "signInType": "emailAddress",
        "issuerAssignedId": "pdhongade007@gmail.com"
      }
    ],
    "displayName": "Sharad Dutta",
    "surname": "",
    "givenName": "",
    "extension_user_type": "user"
  },
  {
    "extension_timezone": "VET",
    "extension_tenant": "EG12345",
    "extension_locale": "en-GB",
    "identities": [
      {
        "signInType": "userName",
        "issuerAssignedId": "pdhongade007"
      }
    ],
    "displayName": "Wayne Rooney",
    "surname": "Rooney",
    "givenName": "Wayne",
    "extension_user_type": "user"
  }
]

This is what I need,这就是我需要的

{
    "extension_timezone": "VET",
    "extension_tenant": "EG12345",
    "extension_locale": "en-GB",
    "signInType": "emailAddress",
    "issuerAssignedId": "pdhongade007@gmail.com",
    "displayName": "Sharad Dutta",
    "surname": "",
    "givenName": "",
    "extension_user_type": "user"
  }

I have to then parse this to CSV, which I know how, I just need to flat this further.然后我必须将它解析为 CSV,我知道如何,我只需要进一步扁平化。 Any help will be appreciated.任何帮助将不胜感激。 I tried looking around, but a lot of them were using external dependencies.我试着环顾四周,但其中很多都在使用外部依赖项。

//UPDATE //更新

{
  "extension_timezone": "VET",
  "extension_tenant": "EG12345",
  "extension_locale": "en-GB",
  "signInType": "userName",
  "displayName": "Wayne Rooney",
  "surname": "Rooney",
  "givenName": "Wayne",
  "issuerAssignedId": "pdhongade007",
  "extension_user_type": "user"
}

When I tried @Jakub solution, I am getting the flat JSON, however it is not iterating for all the users.当我尝试@Jakub 解决方案时,我得到了平面 JSON,但它并没有为所有用户迭代。 Just one!(I am guessing the last user only)只有一个!(我猜只有最后一个用户)

You can traverse the json and just store the "leafs" in map.您可以遍历 json 并将“叶子”存储在地图中。 Note: array of primitives will turn into the last value in the array with this approach, but that's what you described :)注意:使用这种方法,原始数组将变成数组中的最后一个值,但这就是您所描述的:)

Something like this:像这样的东西:

void flatJson() throws JSONException {
    JSONObject object = new JSONObject(userJsonAsString); // this is your input
    Map<String, Object> flatKeyValue = new HashMap<>();
    readValues(object, flatKeyValue);
    System.out.println(new JSONObject(flatKeyValue)); // this is flat
}

void readValues(JSONObject object, Map<String, Object> json) throws JSONException {
    for (Iterator it = object.keys(); it.hasNext(); ) {
        String key = (String) it.next();
        Object next = object.get(key);
        readValue(json, key, next);
    }
}

void readValue(Map<String, Object> json, String key, Object next) throws JSONException {
    if (next instanceof JSONArray) {
        JSONArray array = (JSONArray) next;
        for (int i = 0; i < array.length(); ++i) {
            readValue(json, key, array.opt(i));
        }
    } else if (next instanceof JSONObject) {
        readValues((JSONObject) next, json);
    } else {
        json.put(key, next);
    }
}

Please try the below approach, this will give you a comma separated format for both user and identifier (flat file per se),请尝试以下方法,这将为您提供用户和标识符(平面文件本身)的逗号分隔格式,

 public static void main(String[] args) throws JSONException, ParseException {
    
            String userJsonFile = "path to your JSON";
            final StringBuilder sBuild = new StringBuilder();
            final StringBuilder sBuild2 = new StringBuilder();
            
            try {
                String userJsonAsString = convert your JSON to string and store in var;
            } catch (Exception e1) {
                e1.printStackTrace();
            }
            JSONParser jsonParser = new JSONParser();
            JSONObject output = (JSONObject) jsonParser.parse(userJsonAsString);
            try {
                
                JSONArray docs = (JSONArray) output.get("users");
                Iterator<Object> iterator = docs.iterator();
                
                
                while (iterator.hasNext()) {
                    JSONObject userEleObj = (JSONObject)iterator.next();
                    JSONArray nestedIdArray = (JSONArray) userEleObj.get("identities");
                    Iterator<Object> nestIter = nestedIdArray.iterator();
                     
                    while (nestIter.hasNext()) {
                        JSONObject identityEleObj = (JSONObject)nestIter.next(); 
                        identityEleObj.keySet().stream().forEach(key -> sBuild2.append(identityEleObj.get(key) + ","));
                        userEleObj.keySet().stream().forEach(key -> {
                            if (StringUtils.equals((CharSequence) key, "identities")) {
                                sBuild.append(sBuild2.toString());
                                sBuild2.replace(0, sBuild2.length(), "");
                            } else {
                                sBuild.append(userEleObj.get(key) + ","); 
                            }
                                
                        });
                         
                    }
                    sBuild.replace(sBuild.lastIndexOf(","), sBuild.length(), "\n");  
                }
                
                System.out.println(sBuild);
                
            } catch (Exception e) {
                e.printStackTrace();
            }
        }

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM