如何在排除某些具有 glob 模式的路径的情况下在 nodejs 中获取文件夹大小？

Question

I want to calculate the total archive file size before archiving to show a progress bar. I have some folder which are exluded from zipping with are defined with a glob pattern. How can you get a folder size with a glob filter?

Answer 1

It appears you can't use regular expressions; you can use https://www.npmjs.com/package/glob and loop through the files that match your glob pattern, and get the size of each. Something roughly like (i haven't tested this code):

const fs = require('fs')
const glob = require('glob')

let totalSize = 0 // bytes
 
// options is optional
glob("**/*.js", options, function (er, files) {
  files.forEach(f => {
    totalSize += fs.statSync(f)
  })
})

Answer 2

With the help of above answer this is the solution

const glob = require('glob');
const fs = require('fs');

function getFolderSizeByGlob(folder, { ignorePattern: array }) {
    const filePaths = glob.sync('**', { // "**" means you search on the whole folder
        cwd: folder, // folder path 
        ignore: array, // array of glob pattern strings
        absolute: true, // you have to set glob to return absolute path not only file names
    });
    let totalSize = 0;
    filePaths.forEach((file) => {
        console.log('file', file);
        const stat = fs.statSync(file);
        totalSize += stat.size;
    });
    return totalSize;
}