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dplyr 按包括日期在内的多个条件过滤

[英]dplyr filter by multiple conditions including date

My dataset:我的数据集:

> as_tibble(wq4)
# A tibble: 58,538 x 4
   Date       Site  Analyte                    Value2
   <date>     <fct> <fct>                       <dbl>
 1 2014-01-10  N2   Ammonia NH3-N               0.01 
 2 2014-01-10  N2   Chlorophyll - a             1.5  
 3 2014-01-10  N2   Filtered Total Phosphorus   0.005
 4 2014-01-10  N2   Oxidised Nitrogen           0.1  
 5 2014-01-10  N2   Total Nitrogen              0.3  
 6 2014-01-10  N2   Total Phosphorus            0.008
 7 2014-01-10  N2   Ammonia NH3-N               0.02 
 8 2014-01-10  N2   Chlorophyll - a             1.4  
 9 2014-01-10  N2   Conductivity                191    
10 2014-01-10  N2   Enterococci                 19    
# … with 58,528 more rows

I want to filter out a certain set of values based on multiple conditions using dplyr. What I've got so far is:我想使用 dplyr 根据多个条件过滤掉一组特定的值。到目前为止我得到的是:

filter(wq4, Site != "N1" & !Date %in% c("2019-04-17", "2019-04-18", "2019-04-19"))

I essentially want to remove any data from the 17th to 19th Apr 2019, only at Site N1 (not any of my other sites).我基本上想删除 2019 年 4 月 17 日至 19 日期间的所有数据,仅在站点 N1(而不是我的任何其他站点)。

I don't think this line of code is working for me.我不认为这行代码对我有用。 It is either the "&" or perhaps dplyr is struggling with the date format?是“&”还是 dplyr 正在与日期格式作斗争?

Any suggestions?有什么建议么? Thanks.谢谢。

Your sample data does not include "N1" , but here's a guess:您的样本数据不包括"N1" ,但这是一个猜测:

filter(wq4, Site != "N1" | !between(Date, as.Date("2019-04-17"), as.Date("2019-04-19")))

will return sites that are not "N1" (any date), and data for site "N1" that are not between those two dates.将返回不是"N1" (任何日期)的站点,以及不在这两个日期之间的站点"N1"的数据。

You can still use your %in% logic if you prefer, I offered !between as an alternative for two reasons:如果你愿意,你仍然可以使用你的%in%逻辑,我提供!between作为替代方案有两个原因:

  1. Date objects are not necessarily integral, diff(c(Sys.Date(), Sys.Date() + 0.1)) returns 0.1 days , showing that it is a floating-point. Date对象不一定是整数, diff(c(Sys.Date(), Sys.Date() + 0.1))返回0.1 days ,表明它是一个浮点数。 If your dates are all clearly integral and nothing has possibly nudged them off of the perfect-day, then your %in% should work just fine, but along the lines of Why are these numbers not equal?如果您的日期显然都是不可或缺的,并且没有什么可能使它们偏离完美的一天,那么您的%in%应该可以正常工作,但是按照为什么这些数字不相等? , floating-point equality is not assured. , 不保证浮点相等。

    As an example:举个例子:

     Sys.Date() # [1] "2020-09-19" Sys.Date() %in% as.Date("2020-09-19") # [1] TRUE (Sys.Date() + 0.1) # [1] "2020-09-19" # still looks integral (Sys.Date() + 0.1) %in% as.Date("2020-09-19") # [1] FALSE
  2. In case you want to span more than a few days, it is more efficient to deal with the start/end dates instead of every... possible... date.如果您想跨越几天以上,处理开始/结束日期而不是每个......可能的......日期会更有效。

Try with:尝试:

library(dplyr)
wq4 %>%
   filter(!(Site == "N1" & 
            Date %in% as.Date(c("2019-04-17", "2019-04-18", "2019-04-19"))))

and the same expression in subset :subset的相同表达式:

subset(wq4, !(Site == "N1" & 
              Date %in% as.Date(c("2019-04-17", "2019-04-18", "2019-04-19"))))

Site == "N1" & Date %in% as.Date(c("2019-04-17", "2019-04-18", "2019-04-19") are the rows which you want to remove. So we add ! sign before it. Site == "N1" & Date %in% as.Date(c("2019-04-17", "2019-04-18", "2019-04-19")是您要删除的行。所以我们在它之前添加!符号。

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