[英]C++ | overload operator << | std::map
I'm trying to overload operator << of a map within a struct, but getting a compilation error:我试图在结构中重载 map 的运算符 <<,但出现编译错误:
no suitable user-defined conversion from "std::_Rb_tree_const_iterator<std::pair<const int, int>>" to "std::_Rb_tree_iterator<std::pair<const int, int>>" exists
不存在从“std::_Rb_tree_const_iterator<std::pair<const int, int>>”到“std::_Rb_tree_iterator<std::pair<const int, int>>”的合适的用户定义转换
ostream& operator<<(ostream& os, const map<int, int>& neighbors)
{
string res;
map<int, int>::iterator it = neighbors.begin();
stringstream ss;
while (it != neighbors.end())
{
ss << "[id: " << it->first << " cost: " << it->second << "] ";
it++;
}
return os << ss;
}
How do I correctly get a reference to the iterator of the map?如何正确获取对 map 迭代器的引用? I can only use C++ 98.
我只能使用 C++ 98。
This is my complete code这是我的完整代码
#pragma once
#include <map>
#include <string>
#include <sstream>
using namespace std;
struct LSA
{
int id;
int seqNum;
map <int, int> neighbors;
friend ostream& operator<<(ostream& os, const LSA& lsa);
friend ostream& operator<<(ostream& os, const map<int, int>& neighbors);
};
ostream& operator<<(ostream& os, const LSA& lsa)
{
return os << "[id: " << lsa.id << " seqNum: " << lsa.seqNum << " (" << lsa.neighbors.size() << " neighbors)";
}
ostream& operator<<(ostream& os, const map<int, int>& neighbors)
{
string res;
map<int, int>::iterator it = neighbors.begin();
stringstream ss;
while (it != neighbors.end())
{
ss << "[id: " << it->first << " cost: " << it->second << "] ";
it++;
}
return os << ss;
}
You have a const
map, hence begin
returns a const_iterator
, not an iterator
.你有一个
const
map,因此begin
返回一个const_iterator
,而不是一个iterator
。 There is no defined operator<<
to accept stringstream
as a second argument, hence use its member function str
, as follows没有定义
operator<<
接受stringstream
作为第二个参数,因此使用它的成员 function str
,如下
ostream& operator<<(ostream& os, const map<int, int>& neighbors)
{
string res;
map<int, int>::const_iterator it = neighbors.cbegin();
stringstream ss;
while (it != neighbors.end())
{
ss << "[id: " << it->first << " cost: " << it->second << "] ";
it++;
}
return os << ss.str();
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.