递归替换字典键中的字符

Question

I'm current working a script that takes an Android application's metadata as a nested dictionary and inserts it to MongoDB. However, since some of the keys include '.' s (due to component names in the APK file), which unfortunately isn't accepted by MongoDB in the version being dealt with. Currently trying to write a recursive script which replace the '.' s to '/' s of the keys in the dict data being inserted, but some keys still aren't changed to fit the requirements.

def fixKeys(dictionary):
    for k,v in dictionary.items():
        if isinstance(v, dict):
            if '.' in k:
                dictionary[k.replace('.','/')] = dictionary.pop(k)
            fixKeys(v)
        else:
            if '.' in k:
                dictionary[k.replace('.','/')] = dictionary.pop(k)
    return dictionary 

Example input:

data = {"gender":"male","name.data": {"last.name":"Arabulut","first.name":"Altay","parents.names":{"father.name":"John","mother.name":"Jennifer"}}, "birthday.data":{"birthday.day":"01","birthday.month":"03","birthday.year":"1977"}}

Any idea as to what might be missing?

Answer 1

after the editing I understood your question more properly, the recursion solution for unknown amount of nested dicts is as below:

def fixKeys(dictionary):
    for k,v in list(dictionary.items()):
        if isinstance(v, dict):
            dictionary[k.replace('.', '/')] = fixKeys(v)
        else:
            dictionary[k.replace('.', '/')] = v
        if "." in k:
            dictionary.pop(k)
    return dictionary

m_dict = {"gender":"male", "name.data": {"last.name":"Arabulut","first.name":"Altay","parents.names":{"father.name":"John","mother.name":"Jennifer"}}, "birthday.data":{"birthday.day":"01","birthday.month":"03","birthday.year":"1977"}}

new_dict = fixKeys(m_dict)
print(str(new_dict))

output:

{'gender': 'male', 'name/data': {'last/name': 'Arabulut', 'first/name': 'Altay', 'parents/names': {'father/name': 'John', 'mother/name': 'Jennifer'}}, 'birthday/data': {'birthday/day': '01', 'birthday/month': '03', 'birthday/year': '1977'}}

very good question. like the coding and debugging!