有没有办法在文本文件中读取arrays，但数组中的元素用分号分隔？

Question

I would like to read the array elements and assign them to the new array called data_array , but elements in the array in the text file are separated by semicolons. How should I do if I want to read them normally as they are separated by commas? Furthermore, I want to read the line one by one.

Contents of file data.txt is as follows:

4; -9; -1; 9; -1; -3; 8; 8; 0; -9; -8 
7; 6; 5; -6; 5; -4; 2; 1; -1; -6; 0; 3; -7; 9; 9; 6; -5; -8; 1; -8; -1; -1
-8; -6; -6; -5; -6; -8; -4; -2; 8; -3; 3; 6; 4; -9; 10; 2; -4; 7; -5; 0; -3; 7; -7; 6; -10; 8; -9; 9; 2; -1; -6; 6; -5; 8; 0; 3; 6; -10; -2; 8; -6; -5; 9; 10
1; 7; -6; 7; 6; 2; 9; 2; 3; 1; 0; 8; 5; 2; 4; 9; -10; 3; -9; 9; -2; 8; -1; 4; -4; -3; -10; -2; -9; -5; 7; 9; -4; 6; 10; -1; -8; 10; -2; 2; -9; 2; -2; 2; 3; 10; 6; 3; -3; -5; -4; 6; -4; -2; 2; -5; 4; -8; 0; -2; -5; -4; 3; 4; -6; -10; 3; -5; -10; -3; 4; 10; 10; 5; -5; 0; 10; 2; 9; 7; -8; -2; 10; 4; 10; 9; 3; -7; 
-3; -9; 5; -10; -3; 3; -7; 8; 8; 1; 8; -10; 0; -6; -10; 3; -10; 1; -1; -2; 10; 3; -3; -10; 9; -3; 9; 6; 2; 3; 6; -10; 1; -4; -1; 8; 5; 7; -6; -9; 1; -6; -9; 8; -7; -5; -4; -1; 10; 8; -10; -3; -10; -5; 1; 0; 5; -6; 7; 3; -8; -9; -8; -6; 3; 4; 0; 5; -9; 8; 7; -2; 0; -7; 7; 1; -2; 10; -7; 3; 10; -10; 5; 3; 3; -7; -3; -6; -3; -4; -6; 4; -1; 10; 7; 1; 5; 6; 0; -8; -6; -5; 6; 9; 2; 2; -8; 3; 2; -8; 1; -2; -10; 3; 8; 3; 6; 2; -5; 6; -8; -6; 10; -1; -7; 9; 3; -8; -9; 3; -2; 2; -9; -6; -2; -9; -4; 7; -6; 3; -5; 5; 4; 6; -7; 0; -4; 8; -9; 3; -1; -7; -9; 1; -5; -3; -2; 0; 4; 4; -3; -5; -8; -3; 0; -1; 5; -9; 5; 2; 4; 3; 3; 4; 10; -2

Here's my attempt:

f = open("data.txt", "r")
data_array = [f.readline()]

array_length = len(data_array)

The output is not what I expected, says the length of the array is only one.

Is there any way that I can improve this much better?

Answer 1

Yes you can do it

import csv
result = []
with open('test.txt', newline='') as csvfile:
    spamreader = csv.reader(csvfile, delimiter=';')
    for row in spamreader:
        result += [int(x) for x in row]

and result

[4, -9, -1, 9, -1, -3, 8, 8, 0, -9, -8, 7, 6, 5, -6, 5, -4, 2, 1, -1, -6, 0, 3, -7, 9, 9, 6, -5, -8, 1, -8, -1, -1]

Answer 2

You could use a for-loop:

f = open("data.txt", "r")
data_array = list()
for line in f.read():
    data_array.append(line.split(";"))

Then, it's possible to convert them to ints using a list comprehension:

for line in f.read():
    data_array.append(int(num) for num in line.split(";"))

Answer 3

This list comprehension reads the numeric values from the file and converts them to ints .

Calling str.splitlines on the contents of the file produces output that's easier to work with than simply looping over the file.

filter (None, line.split(';')) gives us the result of line.split (';') with empty strings removed.

data_array = [int(n) for line in f.read().splitlines()
              for n in filter(None, line.split(';'))]

It's the equivalent of this code:

data_array = []
for line in f.read().splitlines():
    for n in line.split(';'):
        n = n.strip()
        if n:
            data_array.append(int(n))