在烧瓶中返回现有的 JSON 文件

Question

i have a method ( matching ) that returns a JSON file. I want to return this file via a flask method.

when i do this:

@app.route('/search', methods=['POST'])
def json_example():
    req_data = request.get_json()
    request_text = req_data['request'] #json text that is needed as argument for calling the matching method
    json_result = matching(request_text)
    return json_result

i get this error:

<title>TypeError: The view function did not return a valid response. The return type must be a string, dict, tuple,
    Response instance, or WSGI callable, but it was a TextIOWrapper. // Werkzeug Debugger</title>

playing around with str(json_result ), i just get this:

<_io.TextIOWrapper name='result.json' mode='w' encoding='UTF-8'>

Also, jsonify(json_reslult) does not work, since i have a json file and am not trying to convert a string into a json. when trying it gives:

<title>TypeError: Object of type TextIOWrapper is not JSON serializable // Werkzeug Debugger</title>

Any helpis greatly appreciated

Answer 1

首先解码 request_text

json_result = matching(json.loads(request_text))