如何在python 3中用'->'分隔单词列表

Question

How do you seperate list of words with '->' or any other char? I tried the .join() method but it doesn't make any change. It seperated the letters just like split with comma.

new_list = ['a' ,'b' ,'c','d']
'->'.join(new_list)
['a', 'b', 'c', 'd']

Answer 1

Without more information information join is the opposite of split. Note that both operation returns a result and do not modify the variable in place. So you will need either to affect the result in a variable or use it directly.

>>> '->'.join(['foo', 'bar', '42'])
'foo->bar->42'

Please provide the value of new_list and how you test it does not work ?

Answer 2

It depends on what do you mean with "list of words".

If, for example, you have a string l = "this, is, a, list, of, words" , you can do:

result = l.replace(', ','->')

which results in this->is->a->list->of->words .

If you need something like: l = ["aba","bac","co"] to "a->b->c" , then:

result = '->'.join(l)

that gives aba->bac->co .