JS提取括号外的所有文本

Question

I need to extract the text outside the square/round brackets.

"WALL COLOR (IS HERE) [SHERWIN-WILLIAMS]"

The expected result is "WALL COLOR" and not "WALL COLOR "

I have tried with

"WALL COLOR (IS HERE) [SHERWIN-WILLIAMS]".match(/\[(.*?)\]/)[0]

Whether a [0] is needed to get result as string instead array.

Answer 1

Assuming your brackets are balanced and there is no escaping etc, It will be easier to do it via .replace . You may use this .replace method to remove all strings that are [...] and (...) surrounded with optional whitespaces on both sides.

str = str.replace( /\s*(?:\[[^\]]*\]|\([^)]*\))\s*/g, "" )
//=> "WALL COLOR"

RegEx Demo

RegEx Details:

• \\s* : Match 0 or more whitespace
• (?: : Start non-capturing group
  • \\[[^\\]]*\\] : Match text that is [...]
  • | : OR
  • \\([^)]*\\) : Match text that is (...)
• ) : End non-capturing group
• \\s* : Match 0 or more whitespace

---

PS: If you want to allow escaped brackets in your input ie WALL COLOR (IS \\(escaped\\) HERE) [SHERWIN-\\[WILL\\]IAMS] then use this bit more complex regex:

/\s*(?:\[[^\\\]]*(?:\\.[^\\\]]*)*\]|\([^\\)]*(?:\\.[^\\)]*)*\))\s*/g

RegEx Demo 2