禁用 ngx-bootstrap 弹出窗口？

Question

Is there a way for a popover to not show over the label if it doesn't meet the condition?

<label [popover]-"popTemplate" popoverTitle="Nicknames">{{label}}</label>

<ng-template #popTemplate>
<li *ngFor="let names of nickNames">
      {{ names }}
    </li>
</ng-template>

Is there something like [isDisabled]="!haveNickNames()" ? or use ngIf in some way?

Answer 1

Given the documentation , you can use the isOpen property

<label [popover]="popTemplate" triggers="" [isOpen]="!haveNickNames">
  {{label}}
</label>