SQL 仅在该值与所有先前值不同时获取行号

Question

I want the count adding one only when the value has not been show before. The base table is:

rownum product   
 1      coke  
 2      coke
 3      burger
 4      burger
 5      chocolate
 6      apple
 7      coke
 8      burger

The goal is:

 rownum product   
 1      coke  
 1      coke
 2      burger
 2      burger
 3      chocolate
 4      apple
 4      coke
 4      burger

I am thinking to compare the current row with all previous rows, but I have difficulty to call all previous rows. Thank you!

Answer 1

This is a gaps-and-islands problem. Here is one approach using window functions: the idea is to use a window sum that increments everytime the "first" occurence of a product is seen:

select t.*, 
    sum(case when rn = 1 then 1 else 0 end) over(order by rownum) new_rownum
from(
    select t.*, row_number() over(partition by product order by rownum) rn
    from mytable t
) t
order by rownum

Answer 2

Several different ways to accomplish this. I guess you'll get to pick one you like the best. This one just finds the first row number per product. You then just need to collapse the holes with an easy application of dense_rank() to the initial grouping.

with data as (
   select *, min(rownum) over (partition by product) as minrow
   from T
)
select dense_rank() over (order by minrow) as rownum, product
from data
order by rownum, data.rownum;