Amazon TranscribeService 的网址

Question

I looked the answer ( URL for public Amazon S3 bucket ) but didn't help. In my aws I have created bucket programmatically and conformed it exist and created Transcribe object and the output is correct. My objective is to create everything programmatically. My mediaFileUri is “https://s3.us-west-2.amazonaws.com/willimbarrsbucket/WillimBarrs.mp4”

using (AmazonTranscribeServiceClient transcribeServiceClient = new 
AmazonTranscribeServiceClient(Amazon.RegionEndpoint.USWest2))
{
    StartTranscriptionJobRequest requestJob = new StartTranscriptionJobRequest()
    {
         TranscriptionJobName = "willimbarrsjob",
         LanguageCode = "en-US",

         Media = new Media()
         {
              MediaFileUri = mediaFileUri
         },
         OutputBucketName = "willimbarrsbucket"
 };

            var responce = await transcribeServiceClient.StartTranscriptionJobAsync(requestJob);

I get an error “The URI that you provided doesn't point to an S3 object. Make sure that the object exists and try your request again”

I am not sure what I am doing wrong? I am using the code from https://net-immersionday.workshop.aws/4-adding-innovation-ai-ml/transcribe.html Any help will be very much appreciated.

Answer 1

FromMedia - Amazon Transcribe :

MediaFileUri

The S3 object location of the input media file. The URI must be in the same region as the API endpoint that you are calling. The general form is:

s3://<AWSDOC-EXAMPLE-BUCKET>/<keyprefix>/<objectkey>

Therefore, you should use:

s3://willimbarrsbucket/WillimBarrs.mp4

Answer 2

When you upload a file, there is a key associated with that file. use that key string mediaFileUri = $"s3-us-west-2.amazonaws.com{bucketName}/{Key}"; Now it works.