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为什么我的变量会导致 Java 溢出?

[英]Why does my variable resut in an overflow in Java?

Here is my code num1 etc are int variable这是我的代码num1等是int变量

double numProduct1;
 numProduct1 = (num1 * num2 * num3 * num4);

System.out.printf("%.3f ", numProduct1);

Inputs are respectively (num1,num2,num3,num4): 100000 200000 300000 500000输入分别为 (num1,num2,num3,num4): 100000 200000 300000 500000

my code would output -1679818752.000 instead of 3000000000000000000000.000我的代码会输出-1679818752.000而不是3000000000000000000000.000

You thought that assigning the product to a double will allow you to use the whole range of double , but that isn't the case.您认为将产品分配给double将允许您使用double的整个范围,但事实并非如此。 You are only converting the result to double .您只是将结果转换为double The multiplication is still carried out with int , and the int range applies.乘法仍然使用int ,并且int范围适用。

Essentially, this is the multiplication version of this common question (well, not exactly :D).本质上,这是这个常见问题的乘法版本(嗯,不完全是:D)。

The fix is similar, simply make the first operand double (eg by casting):修复方法类似,只需将第一个操作数double (例如通过强制转换):

numProduct1 = ((double)num1 * num2 * num3 * num4);

The expression is now a double multiplied by an int , and numeric promotion occurs, promoting the other numbers to double as well.该表达式现在是一个double乘以一个int ,并且发生了数字提升,从而将其他数字也提升为double

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