如何使用 selenium 单击按钮 - 网站

Question

I'd like to open the http inside the code below and click on the graph button that show the candlestick. This is because then I'd like to perfrom a screenshot and save the graph image of the title. Could you help me?

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from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import time

PATH="C:\Program Files (x86)\chromedriver.exe"
driver= webdriver.Chrome(PATH)
driver.get("https://www.plus500.it/Instruments/TSLA")


try:
    element=WebDriverWait(driver,30).until(EC.element_to_be_clickable(By.ID, "ButtonLine"))
    element.click()

except:
    print('not found')
    driver.quit()

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Answer 1

The error you were getting (but didn't appear as you wear using try...except) was :

    Traceback (most recent call last):
  File "C:/Users/PycharmProjects/pythonProject3/main.py", line 14, in <module>
    element=WebDriverWait(driver,30).until(EC.element_to_be_clickable(By.ID, "ButtonLine"))
TypeError: __init__() takes 2 positional arguments but 3 were given

Reason: You forgot a parenthesis

Fix:

element=WebDriverWait(driver,30).until(EC.element_to_be_clickable((By.ID, "ButtonLine")))

Just tested it, it works fine.

Answer 2

您可以像这样找到元素并在.click()之后添加：

find_element_by_xpath(xpath to element).click() 

Answer 3

You should write this code as given below

xpath = browser.find_element_by_xpath('TYPE THE XPATH')
xpath.click()