[英]QStateMachine procedural transition (i.e. Signal)
I need to be able to change state of a QStateMachine from a Signal (or something equivalent) that was not generated by user interaction (ie by a process completing).我需要能够从不是由用户交互(即通过进程完成)生成的信号(或等效的东西)更改 QStateMachine 的状态。 This example redirectsa user generated signal to demonstrate the idea, but doesn't yet work.
这个例子重定向用户生成的信号来演示这个想法,但还没有工作。 Here, the push button signals fire other signals that I want to use for the transition.
在这里,按钮信号会触发我想用于转换的其他信号。 The states here are
B1 <-> B2
where Bi -> Bj
on the redirected signal when button bi
is pressed.这里的状态是
B1 <-> B2
其中Bi -> Bj
在按下按钮bi
时重定向的信号。
The QStateMachine documentation only seems to cover transitions based on direct signals from buttons and I haven't been able to extrapolate to the more general case of using any Signal (ie one that I create). QStateMachine 文档似乎只涵盖基于来自按钮的直接信号的转换,我无法推断使用任何信号(即我创建的信号)的更一般情况。
import sys
from PySide2.QtCore import Qt, QStateMachine, QState, Signal as QSignal
from PySide2.QtWidgets import QApplication, QMainWindow, QPushButton, QVBoxLayout, QWidget
class MainWindow(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
self.w = QWidget()
self.setCentralWidget(self.w)
l1 = QVBoxLayout()
self.b1 = QPushButton("B1", self.w)
self.b1.pressed.connect(self.b1Pressed)
l1.addWidget(self.b1)
self.b2 = QPushButton("B2", self.w)
self.b2.pressed.connect(self.b2Pressed)
l1.addWidget(self.b2)
self.w .setLayout(l1)
self.setupStateMachine()
self.show()
def b1Pressed(self):
print("b1 pressed")
self._b1Pressed.emit()
def b2Pressed(self):
print("b2 pressed")
self._b2Pressed.emit()
def setupStateMachine(self):
self._b1Pressed = QSignal()
self._b2Pressed = QSignal()
self.sm = QStateMachine()
self.B1 = QState()
self.B1.assignProperty(self.b1, "enabled", True)
self.B1.assignProperty(self.b2, "enabled", False)
self.sm.addState(self.B1)
self.B2 = QState()
self.B2.assignProperty(self.b1, "enabled", False)
self.B2.assignProperty(self.b2, "enabled", True)
self.sm.addState(self.B2)
# The point of it all:
# change states from a signal (or program generated event)
self.B1.addTransition(self._b1Pressed, self.B2)
self.B2.addTransition(self._b2Pressed, self.B1)
if __name__ == '__main__':
app = QApplication(sys.argv)
window = MainWindow()
sys.exit(app.exec_())
Your code has the following problems:您的代码存在以下问题:
class MainWindow(QMainWindow):
_b1Pressed = QSignal() _b2Pressed = QSignal()
def __init__(self):
QMainWindow.__init__(self)
self.w = QWidget()
self.setCentralWidget(self.w)
l1 = QVBoxLayout()
self.b1 = QPushButton("B1", self.w)
self.b1.pressed.connect(self.b1Pressed)
l1.addWidget(self.b1)
self.b2 = QPushButton("B2", self.w)
self.b2.pressed.connect(self.b2Pressed)
l1.addWidget(self.b2)
self.w.setLayout(l1)
self.setupStateMachine()
self.show()
def b1Pressed(self):
print("b1 pressed")
self._b1Pressed.emit()
def b2Pressed(self):
print("b2 pressed")
self._b2Pressed.emit()
def setupStateMachine(self):
self.sm = QStateMachine()
self.B1 = QState()
self.B1.assignProperty(self.b1, "enabled", True)
self.B1.assignProperty(self.b2, "enabled", False)
self.sm.addState(self.B1)
self.B2 = QState()
self.B2.assignProperty(self.b1, "enabled", False)
self.B2.assignProperty(self.b2, "enabled", True)
self.sm.addState(self.B2)
# The point of it all:
# change states from a signal (or program generated event)
self.B1.addTransition(self._b1Pressed, self.B2)
self.B2.addTransition(self._b2Pressed, self.B1)
self.sm.setInitialState(self.B1) self.sm.start()
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