根据 DataFrame 中的过滤条件将正值转换为负值

Question

user_id           date         type        transaction_part_sum     transaction_part_count
1000616411022604  2011-12-20   debit                51.58                       1
1000616411022604  2013-06-10   debit                25.52                       1
1000616411022604  2013-11-07   credit               533.29                      1
1000616411022604  2013-12-26   debit                3.82                        1
1000616411022604  2013-12-31   credit               259.68                      1
1000616411022604  2014-01-02   debit                79.10                       1
1000616411022604  2014-02-25   debit                9.99                        1
1000616411022604  2014-03-26   debit                3.42                        1
1000616411022604  2014-04-02   debit                71.90                       1

In a pandas DataFrame as shown above, I want to change the debit row of the "transaction_part_sum" to negative value.

I did this

grouped.loc[grouped['type'] == 'debit', 'transaction_part_sum'] = -1 * grouped['transaction_part_sum']

but when printing grouped. The values in the debit row don't get populated. If I multiply with any other positive number I get the values populated. How can I change the debit row to negative value?

output: 
user_id           date         type         transaction_part_sum      transaction_part_count
1000616411022604  2011-12-20   debit                                            1
1000616411022604  2013-06-10   debit                                            1
1000616411022604  2013-11-07   credit               533.29                      1
1000616411022604  2013-12-26   debit                                            1
1000616411022604  2013-12-31   credit               259.68                      1
1000616411022604  2014-01-02   debit                                            1
1000616411022604  2014-02-25   debit                                            1
1000616411022604  2014-03-26   debit                                            1
1000616411022604  2014-04-02   debit                                            1

Answer 1

Your solution for me working, also should be simplify with mutiple by constant by *= statement:

EDIT: There is dtype for column amount object, it means obviously strings, so first is necessary convert to numeric:

dataframe = pd.DataFrame(dataList, columns=['user_id', 'account_id','amount','randString','date','type','string'])
dataframe['amount'] = dataframe['amount'].astype(float)

grouped = dataframe.groupby(['user_id','date','type']).agg({'amount':['sum','count']}).sort_values(by='date')
grouped.loc[grouped['type'] == 'debit', 'transaction_part_sum'] *= -1
print (grouped)
            user_id        date    type  transaction_part_sum  \
0  1000616411022604  2011-12-20   debit                -51.58   
1  1000616411022604  2013-06-10   debit                -25.52   
2  1000616411022604  2013-11-07  credit                533.29   
3  1000616411022604  2013-12-26   debit                 -3.82   
4  1000616411022604  2013-12-31  credit                259.68   
5  1000616411022604  2014-01-02   debit                -79.10   
6  1000616411022604  2014-02-25   debit                 -9.99   
7  1000616411022604  2014-03-26   debit                 -3.42   
8  1000616411022604  2014-04-02   debit                -71.90   

   transaction_part_count  
0                       1  
1                       1  
2                       1  
3                       1  
4                       1  
5                       1  
6                       1  
7                       1  
8                       1  

Answer 2

You can do a simple command to multiply it by -1.

import pandas as pd
df = pd.DataFrame({'trans':[10,20,30,40]})
print (df)
df['trans'] *= -1
print (df)

This will print the results as follows:

   trans
0     10
1     20
2     30
3     40
   trans
0    -10
1    -20
2    -30
3    -40

You can do the same even for a condition.

df.loc[df['trans'] == 20,'trans'] *= -1
print (df)

This will result in -20 but all others say as is.

   trans
0     10
1    -20
2     30
3     40

Answer 3

你可以试试 numpy.where

grouped['transaction_part_sum'] = np.where(grouped.type == 'debit', -1 * grouped.transaction_part_sum, grouped.transaction_part_sum)