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打字稿访问嵌套条件类型

[英]Typescript access nested conditional type

I am trying to access the nested type b given the following type definition and that a is not null:我正在尝试根据以下类型定义访问嵌套类型 b 并且 a 不为空:

type Abc = {
  a: {
    b: number
  } | null
}

However, the following code causes an error: Property 'b' does not exist on type '{ b: number; } | null'.ts(2339)但是,以下代码会导致错误: Property 'b' does not exist on type '{ b: number; } | null'.ts(2339) Property 'b' does not exist on type '{ b: number; } | null'.ts(2339)

const test: Abc["a"]["b"] = 3;

You could change it to:您可以将其更改为:

const test: NonNullable<Abc["a"]>["b"] = 3;

That's a bit of a mouthful though.不过还是有点口无遮拦。 You could also consider splitting it into a couple interfaces, and referring to the inner one directly:您也可以考虑将其拆分为几个接口,并直接引用内部接口:

interface Thing {
  b: number
}

type Abc = {
  a: Thing | null
}

const test: Thing["b"] = 3;

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