Pandas 中的两个列表比较

Question

I have two list, first one with names only and second one with names and values corresponding to names. What I am trying to achieve is to find in second list all names that presented in first list with its values in second one. I tried this way, but missing the corresponding numbers

matches = []
for i in list(first):
    if i in list(second]):
       matches.append(i)

Plz Help

Answer 1

if it has names and values corresponding to names - it is not a list, but dict or pd.DataFrame

for pd.DataFrame:

matches = list2[list2.name.isin (list1)]

for dict:

matches = {}
for i, v in dict2.items():
    if i in list1:
       matches[i] = v

or just matches = {i:v for i in dict2 if i in list1}