[英]Remove middle of name in bash
I have 300+ files named:我有 300 多个文件名为:
T1_0000106_FS1_MAX_5743.nii.gz T1_0000214_FS1_MAX_5475.nii.gz
T1_0000107_FS1_MAX_5477.nii.gz T1_0000215_FS1_MAX_6162.nii.gz
I would like to remove everything between T1 and _5/6*.nii.gz so:我想删除 T1 和 _5/6*.nii.gz 之间的所有内容,因此:
T1_5743.nii.gz T1_5475.nii.gz
T1_5477.nii.gz T1_6162.nii.gz
I can't figure out why it isn't working;我不知道为什么它不起作用; I tried (from another post):
我尝试过(来自另一篇文章):
for file in *.gz;
do new_name=$(sed 's/_[^.]*_/_g' <<< "new_name");
mv "$file" "$new_name"; done
and variations of rename/sed but nothing changes.和 rename/sed 的变体,但没有任何变化。
Problems with your script include, at least,你的脚本问题至少包括,
s/_[^.]*_/_g
is not a valid sed
command. s/_[^.]*_/_g
不是有效的sed
命令。 You appear to want s/_[^.]*_/_/g
, or in this case, s/_[^.]*_/_/
would do fine as well.您似乎想要
s/_[^.]*_/_/g
,或者在这种情况下, s/_[^.]*_/_/
也可以。
<<< "new_name"
redirects the literal string new_name
into sed
. <<< "new_name"
将文本字符串new_name
重定向到sed
。 Possibly you mean <<< "$new_name"
可能你的意思是
<<< "$new_name"
Personally, though, I would not bother with sed
for this job, especially if you have a large number of files.不过,就我个人而言,我不会为这项工作费心使用
sed
,尤其是当您有大量文件时。 Bash is perfectly capable of doing fairly complex string manipulation itself, and your needs don't push it too hard. Bash 本身完全有能力进行相当复杂的字符串操作,您的需求不会太强。 Consider:
考虑:
for f in *.gz; do
# The value of $f with the longest trailing match to _* removed
head=${f%%_*}
# The value of $f with the longest leading match to *_ removed
tail=${f##*_}
new_name="${head}_${tail}"
# Sanity check and avoid needless errors
if [ "$f" != "$new_name" ]; then
mv "$f" "$new_name"
fi
done
You could do你可以做
for i in *_5*.nii.gz *_6*.nii.gz;do a=${i%%_*};b=${i##*_};[[ $i != $a"_"$b ]] && mv $i $a"_"$b;done
Edited Following suggestion that the file could already be renamed.编辑以下建议该文件已经可以重命名。
Bash's built-in string substitution and its extglob
option simplify the replacement of the middle part: Bash 的内置字符串替换及其
extglob
选项简化了中间部分的替换:
#!/usr/bin/env bash
shopt -s extglob
for file in T1_*.nii.gz; do
echo mv -- "$file" "${file/_+([^.])_/_}"
done
Remove the echo
or pipe the output to a shell, if it matches your expectations.如果符合您的期望,则删除
echo
或将输出通过管道传输到 shell。
Here is the output of my own test:这是我自己测试的输出:
mv -- T1_0000106_FS1_MAX_5743.nii.gz T1_5743.nii.gz
mv -- T1_0000107_FS1_MAX_5477.nii.gz T1_5477.nii.gz
mv -- T1_0000214_FS1_MAX_5475.nii.gz T1_5475.nii.gz
mv -- T1_0000215_FS1_MAX_6162.nii.gz T1_6162.nii.gz
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