在数组中查找 MAX 偶数和奇数值

Question

I need to find the MAX even and odd values of a given array. In this case I need the console to print that the max even is 8 and the max odd is 11 This is revised from another question because of the cool down time for asking questions

import java.util.Scanner;
public class Question03 {

    public static int[] array;//The array to be used in the problem
    public static void main(String[] args) {
        int number;//Used for the stairs
        if(args == null || args.length == 0)
        {

            int[] tempArray ={2,4,6,8,11};//You may change these values to test 
            array = tempArray;
        }
        else
        {

        }

        //Write your solution here
        int evenMax = array[0];
        int oddMax = array[0];
        for (int x =1; x<array.length; x++){
            if(evenMax %2 == 0)
            {
                 if (evenMax<array[x])
                 {
                   
                 }
          }
          if(oddMax<array[x]){
            oddMax=array[x];
          }
        }

        System.out.println("The largest number is: " + evenMax + ". The smallest number is: " +oddMax);
        

Answer 1

You can use Streams from Java 8 along with Optional:

import java.util.Arrays;

public static void main(String[] args) {
    int[] array = {1,2,3};
    Arrays
        .stream(array)
        .filter(n -> n > 0)
        .average()
        .getAsDouble();
}

vide: DoubleStream and OptionalDouble

Answer 2

Just fixing your code, I added a variable to store the number of elements that should be used as divisor when calculating the average value. In this case total store the sum of all elements in the array.

int elements = array.length;
double total = 0;
for(int i=0; i<array.length; i++)
{
    if(array[i] < 0)
    {
        array[i] = 0;
    }
    if(array[i] == 0)
    {
        elements--;
    }
    total += array[i];
}
double average = total / elements;

System.out.println("the average was " +average);

PS As any algorithm there are many ways to solve this problem. But, here, my intent was to help you according to your line of thought.

Answer 3

How about something like this:

    double total = 0;
    int count = 0;
    for(int i=0; i<array.length; i++)
    {
        if(array[i] > 0)
        {
            total += array[i];
            ++count;
        }
    }
    double average = total / count;
    System.out.println("the average was " +average);

Or even:

    double total = 0;
    int count = 0;
    for(double value: array)
    {
        if(value > 0)
        {
            total += value;
            ++count;
        }
    }
    double average = total / count;
    System.out.println("the average was " +average);