通过比较来自另一本字典的键，从一本字典返回值

Question

I have two dictionaries and I want to get the values of the first dictionary for the keys of the second. Both the dictionaries have the same keys but in different order. For example:

dict1={'a':1,'b':1,'c':0,'d':0,'e':1,'f':0,'g':1}

This is the first dictionary. And the second dictionary is:

dict2={'c':3,'b':2,'a':1,'d':1,'e':0,'g':0,'f':0}

I want to get the values corresponding to the first dictionary but in the order of keys of the second dictionary. So the output should be like this:

dict3={'c':0,'b':1,'a':1,'d':0,'e':1,'g':1,'f':0}

Is there any way to do that?

Answer 1

If you have you have Python 3.7+ you can use this:

dict1={'a':1,'b':1,'c':0,'d':0,'e':1,'f':0,'g':1}
dict2={'c':3,'b':2,'a':1,'d':1,'e':0,'g':0,'f':0}

dict3 = {k: dict1[k] for k in dict2.keys()}
print(dict3)

> {'c': 0, 'b': 1, 'a': 1, 'd': 0, 'e': 1, 'g': 1, 'f': 0}

What's New In Python 3.7

the insertion-order preservation nature of dict objects has been declared to be an official part of the Python language spec.

Answer 2

Is this what you meant?

dict3 = {key:dict1[key] for key in dict2.keys()}

Tried on python 3.9.