如何通过在laravel中传递参数来获得内容类型application/x-www-form-urlencoded的响应

Question

I have used Api on to Single Sign In Opt with in Laravel https://sso/{custom_path}/token like this Api created using jwt. And on my end in web application passing access token and content type in header to Api call using http client guzzle. With content type application/x-www-form-urlencoded with parameters in form_params. But in response i am getting missing grant_type. As i am passing grant_type in form_parms array. Is there any other way to resolve this issue. Any valueable response will be considered.

Code:

$uri = $this->userTokenAuthencticateUrl();
        $token = session('token')->access_token;
        $params['header'] = [
            "Content-Type: application/x-www-form-urlencoded",
            "Authorization: Bearer $token"
            ];
        $params['form_params'] = array(
                'grant_type' => 'xxxxx',
                'response_include_resource_name' => 'xxx',
                'audience' => 'xxxx', 
                'permission' => 'xxxxxx',
            );
            $response = Http::post($uri, $params);
            dd($response->json());

Ressponse:

array:2 [▼
  "error" => "invalid_request"
  "error_description" => "Missing form parameter: grant_type"
]

Answer 1

As you are using HTTP Client. You need to change your code. You do not need to pass Content-Type as application/x-www-form-urlencoded in your header and I believe the Authorization token is passed separately in headers you can pas it in your params.

$uri = $this->userTokenAuthencticateUrl();
$token = session('token')->access_token;

 $params = array(
        'grant_type' => 'xxxxx',
        'response_include_resource_name' => 'xxx',
        'audience' => 'xxxx', 
        'permission' => 'xxxxxx',
 );
 $response = Http::asForm()->withHeaders([
        'Authorization' => 'Bearer ' . $token
     ])->post($uri, $params);

 dd($response->json());

Method 2:

It is also mentioned in docs

If you would like to quickly add an Authorization bearer token header to the request, you may use the withToken method so you can do like this as well

$uri = $this->userTokenAuthencticateUrl(); $token = session('token')->access_token; $params = array( 'grant_type' => 'xxxxx', 'response_include_resource_name' => 'xxx', 'audience' => 'xxxx', 'permission' => 'xxxxxx', ); $response = Http::asForm()->withToken($token)->post($uri, $params); dd($response->json());

See the doc for more details

---

Method 3:

You can even directly use guzzle as well.

 define("form_params", \\GuzzleHttp\\RequestOptions::FORM_PARAMS ); try{ $client = new \\GuzzleHttp\\Client(['headers' => ['Authorization' => 'Bearer ' . $token]]); $guzzleResponse = $client->post( $api_url, [ 'form_params' => [ 'grant_type' => 'xxxxx', 'response_include_resource_name' => 'xxx', 'audience' => 'xxxx', 'permission' => 'xxxxxx' ] ]); if ($guzzleResponse->getStatusCode() == 200) { $response = json_decode($guzzleResponse->getBody(),true); //perform your action with $response } } catch(\\GuzzleHttp\\Exception\\RequestException $e){ // you can catch here 400 response errors and 500 response errors // see this https://stackoverflow.com/questions/25040436/guzzle-handle-400-bad-request/25040600 }catch(Exception $e){ //other errors }