如何在函数调用中使用打字稿泛型类构造函数作为参数

Question

I am trying to use the following API from the package typescript-json-serializer .

export declare function deserialize<T>(json: object, type: new (...params: Array<any>) => T): T;

A simple working sample code for this API usage is:

const result: MyClass = deserialize<MyClass>(json, MyClass);

My usage is a little more tricky. Instead of MyClass , I would like to have a generic class, something like MyClass<T> .

I tried the following, but it is failing to compile

const result: MyClass<T> = deserialize<MyClass<T>>(json, MyClass<T>);

The mentioned error is Value of type 'typeof MyClass' is not callable. Did you mean to include 'new'? Value of type 'typeof MyClass' is not callable. Did you mean to include 'new'?

Any idea how to solve this ?

Updates : In my last exemple, T is a real class.

const result: MyClass<MyClass2> = deserialize<MyClass<MyClass2>>(json, MyClass<MyClass2>);

Answer 1

The generic parameter of the constructor is implied by the T annotation on deserialize . The correct and typesafe syntax is:

deserialize<MyClass<T>>(json, MyClass);