从响应中的 php 数组解析 html 标签

Question

Having the next array:

$link = 'Link ' . '<a href="https://google.com">Learn more...</a>';
$array = ['1' => 'normal string text', '2' => $link];
return $array;

The response would be:

1 "normal string text"

2 "Link, <a href="https://google.com">Learn more..."

The result expected would be that the a tag would get parsed: Link, Learn more...

Tried with different solutions, but nothing seems to be working. Any ideas?

Thanks

Edited: The result should be an array in which one of the entries would be that link already parsed and ready to be used.

Answer 1

well you'r code is correct but you are returning the array outside a function you need to add it to a function and call it

ex:

  public function printArray(){
  $link = 'Link ' . '<a href="https://google.com">Learn more...</a>';
  $array = ['1' => 'normal string text', '2' => $link];
  return $array;
 }
 
//callback
 
echo printArray();

or if you want to pass some params

public function printArray($link , $text){
  $link = $link;
  $array = ['1' => $text, '2' => $link];
  return $array;
 }

    //callback 
  $link = 'Link ' . '<a href="https://google.com">Learn more...</a>';
  $text='normal string text';
 
echo printArray($link,$text);
 

or just print it like this:

$link = 'Link ' . '<a href="https://google.com">Learn more...</a>';
$array = ['1' => 'normal string text', '2' => $link];

print($array[0]);//output : normal string text 
print($array[1]);//output :  Link Learn more...

Answer 2

you can use:

$link = 'Link ' . '<a href="https://google.com">Learn more...</a>';
$elements = ['1' => 'normal string text', '2' => $link];


foreach($elements as $key => $element){
    echo "{$key} {$element} <br>";
}

Answer 3

I don't know if this will work since I haven't tested it but you could try:

<?php
$array->data[] = array(
  'Your text', 
  '<a href="https://google.com"><u>Learn more...</u></a>'
);
echo $array
?>