有没有一种不那么奇怪的方法来生成这个虚拟数据？

Question

Input: a list of word_types eg ["verb", "adjective", "name", "noun]

Desired output: a dictionary of three words for each letter-word_type combination arranged by word_type.

ie

{"verbs" : ["Averb1", "Averb2", "Averb3"], [Bverb1, ...], ..., "adjectives" : ["Aadjective1","Aadjectives2", "Aadjectives3"] ... etc

Here's what I used to generate my data.

import string
A_to_Z = list(string.ascii_uppercase)  #  list of letters a-z
lettered_word_types = ["verb", "adjective", "name", "noun"]

class Lexicon:
    def __init__(self, testing = True):
        if testing == True:
            for TYPE in lettered_word_types:
                setattr(self, TYPE + "s", [letter + TYPE for letter in A_to_Z])
        self.__dict__ = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in self.__dict__.items()}


data = Lexicon().__dict__

Answer 1

The class serves no purpose, it simply obfuscates what you are doing. To transliterate your code to use a dict directly, you just need:

result = {}
for TYPE in lettered_word_types:
    result[TYPE + 's'] = [letter + TYPE for letter in A_to_Z]
result = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in result.items()}

So, just to show that this is indeed equivalent:

In [1]: import string
    ...: A_to_Z = list(string.ascii_uppercase)  #  list of letters a-z
    ...: lettered_word_types = ["verb", "adjective", "name", "noun"]
    ...:
    ...: class Lexicon:
    ...:     def __init__(self, testing = True):
    ...:         if testing == True:
    ...:             for TYPE in lettered_word_types:
    ...:                 setattr(self, TYPE + "s", [letter + TYPE for letter in A_to_Z])
    ...:         self.__dict__ = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in self.__dict__.items()}
    ...:
    ...:
    ...: data = Lexicon().__dict__

In [2]: result = {}

In [3]: for TYPE in lettered_word_types:
    ...:     result[TYPE + 's'] = [letter + TYPE for letter in A_to_Z]
    ...:

In [4]: result = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in result.items()}

In [5]: result == data
Out[5]: True