[英]mime_content_type(): Invalid path
I am creating a picture with text on it like this:我正在创建一张带有文字的图片,如下所示:
createImage.php
function randExer() {
//Creates a black picture
$img = imagecreatetruecolor(200, 50);
//uses RGB-values to create a useable color
$textColor = imagecolorallocate($img, 255, 255, 255);
$linesColor = imagecolorallocate($img, 192, 192, 192);
//Adds text
imagestring($img, 5, 18, 18, "four + five = ?", $textColor);
$rotate = imagerotate($img, $angle, 0);
ob_start();
imagejpeg($rotate);
$contents = ob_get_contents();
ob_end_clean();
$imageData = base64_encode($contents);
$src = "data:" . mime_content_type($contents) . ";base64," . $imageData;
return "<img alt='' src='" . $src . "'/>";
}
Result结果
To actually show the created image in html, I use this:要在 html 中实际显示创建的图像,我使用:
<label id='exercise'>
<?php
echo randExer();
?>'
</label><br>
The functionality itself is working fine and the result looks like this - which is how it is supposed to look:功能本身运行良好,结果如下所示 - 它应该是这样的:
Problem问题
The problem is that I get the following warning:问题是我收到以下警告:
Warning: mime_content_type(): Invalid path in createImage.php on line 19
I don't really know what's wrong with the path.我真的不知道路径有什么问题。
What is the problem here?这里有什么问题?
mime_content_type requires path to the tested file, not just base64 string. mime_content_type 需要测试文件的路径,而不仅仅是 base64 字符串。 But why are you trying to recognize mime type when you know it is image/jpeg (by imagejpeg function).
但是,当您知道它是 image/jpeg(通过 imagejpeg 函数)时,为什么还要尝试识别 mime 类型。
$src = "data:image/jpeg;base64," . $imageData;
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