我可以循环遍历python中的逻辑运算符吗？

Question

In order to avoid repetition, I would like to do something like this:

a, b = True, False
l = list()
for op in [and, or, xor]:
    l.append(a op b)

I tried import operator and also itertools , but they do not contain logical operators, just math and some other ones.

I could not find any previous answer that was helpful!

Answer 1

Your example can be implemented using the operator module.

from operator import and_, or_, xor

ops = [and_, or_, xor]
l = [op(a,b) for op in ops]

These are bitwise operators, but for booleans -- which are represented in only one bit -- they double as logical operators.

Answer 2

or and and can't really be replicated by functions because they short-circuit; but if you don't care about that you can write lambda functions, eg lamba x, y: x and y . For xor on booleans you could use operator.ne .

ops = [(lambda x,y: x and y), (lambda x,y: x or y), operator.ne]
l = [op(a,b) for op in ops]

The list comprehension was suggested by Adrian W in the comments.

Update: Use stfwn's answer . It's better.