给定数组，写一个 function 找到最大值并返回匹配的字符串

Question

I have been given an array and need to write a function mostExpensiveItemName(items) and have it return the largest number in the array and return the items name.

Example output:

mostExpensiveItemName(items) //=> "Creation 3005"

Given array:

let items = [
  {
    itemName: "Effective Programming Habits",
    type: "book",
    price: 13.99
  },
  {
    itemName: "Creation 3005",
    type: "computer",
    price: 299.99
  },
  {
    itemName: "Finding Your Center",
    type: "book",
    price: 15.00
  }
]

What I have:

function mostExpensiveItemName(items) {
  if (items.length === 0) return undefined;
  let mostExpensive = items.reduce((total, items) => items.price > total.price ? items : total);

  return mostExpensive.itemName;
}

My solution works but I was wondering if there was a super elementary way of writing it. With a for loop or max() method

Answer 1

I have been given an array and need to write a function mostExpensiveItemName(items) and have it return the largest number in the array and return the items name.

Example output:

mostExpensiveItemName(items) //=> "Creation 3005"

Given array:

let items = [
  {
    itemName: "Effective Programming Habits",
    type: "book",
    price: 13.99
  },
  {
    itemName: "Creation 3005",
    type: "computer",
    price: 299.99
  },
  {
    itemName: "Finding Your Center",
    type: "book",
    price: 15.00
  }
]

What I have:

function mostExpensiveItemName(items) {
  if (items.length === 0) return undefined;
  let mostExpensive = items.reduce((total, items) => items.price > total.price ? items : total);

  return mostExpensive.itemName;
}

My solution works but I was wondering if there was a super elementary way of writing it. With a for loop or max() method

Answer 2

function mostExpensiveItemName(items) {
    let counter = 0;
        //assign name to return later with conditional
    let name;
    for (let i = 0; i < items.length; i++){
        const e = items[i];
            /* conditional holds price value in the counter variable 
            while it cycles through the loop */
        if (e.price > counter){
            counter = e.price;
                //if true, condition also assigns name to e.itemName
            name = e.itemsName;
            }
        }
    return name;
}