[英]How do I convert an Int to an Int[] in java?
I want to convert a primitive Java integer value:我想转换一个原始的 Java 整数值:
int myInt = 4821;
To an integer array:对于整数数组:
int[] myInt = {4, 8, 2, 1};
public static void main(String[] args) {
int myInt = 4821;
int size = 0;
int temp = myInt;
while(temp > 0) {
temp = temp/10;
size++;
}
int[] numbers = new int[size];
int index = 0;
while(myInt > 0) {
numbers[index] = myInt % 10;
myInt = myInt / 10;
index++;
}
for (int i : numbers) {
System.out.println("Number : "+i);
}
}
output输出
Number : 1
Number : 2
Number : 8
Number : 4
Following code for a simple one line solution using Java 8+ with Stream
and mapToInt
:以下代码用于使用Java 8+和
Stream
和mapToInt
的简单单行解决方案:
Stream.of(String.valueOf(myInt).split("")).mapToInt(Integer::parseInt).toArray();
Generic solution:通用解决方案:
import java.util.stream.Stream;
public static int[] convertValueToIntegerArray(int value) {
return Stream.of(String.valueOf(value).split(""))
.mapToInt(Integer::parseInt)
.toArray();
}
Example:例子:
import java.util.Arrays;
public void testIntegerArray() {
int myInt = 4821;
int[] myIntArr = convertValueToIntegerArray(myInt);
System.out.println("Testing Integer Array converted: " + Arrays.toString(myIntArr));
}
There can be so many ways to do it.可以有很多方法来做到这一点。 A concise way of doing it is by using
Stream
API as shown below:一种简洁的方法是使用
Stream
API,如下所示:
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
int myInt = 4821;
int[] arr =
String.valueOf(Math.abs(myInt)) // Convert the absolute value to String
.chars() // Get IntStream out of the String
.map(c -> c - 48) // Convert each character digit into numeric value
.toArray(); // Convert the stream into array
// Display the array
System.out.println(Arrays.toString(arr));
}
}
Output:输出:
[4, 8, 2, 1]
Notes:笔记:
'0'
is 48
, that of '1'
is 49
and so on. '0'
ASCII 值是48
, '1'
ASCII 值是49
等等。Math#abs
returns the absolute value of an int
value eg Math.abs(-5) = 5
and Math.abs(5) = 5
Math#abs
返回int
值的绝对值,例如Math.abs(-5) = 5
和Math.abs(5) = 5
int myInt = 4821;
String myIntText = myInt+ ""; //Implicit cast to String
Integer[] numberArray = new Integer[myIntText.length()]; //Create Array for result
for(int i=0; i<myIntText.length(); i++) {
String number = myIntText.substring(i, i+1); //Extract every number from left to right
numberArray[i] = Integer.valueOf(number); //save the number in the array
}
for(int i = 0; i<myIntText.length(); i++)
System.out.println(numberArray[i]);
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