如何纠正我在石头剪刀布游戏中的错误

Question

I have a problem figuring out how to define rock and determine_winner I'm hoping someone could check out what I have and tell me were i'm going wrong. Also sometimes I get the program to run when I put it def main(): but it makes it spam in loop instead of hitting yes to play the game. Also am wondering if any of my indentations are wrong and if that could be the problem at hand.

import random
def process_computer_choice(): 

    return random.randint(1,3)

def process_player_choice():

    pass
def main():

    def computer_choice():
        return random.choice([1,2])
play_again = 'y'
number_of_tied_games = 0
number_of_player_games = 0
number_of_computer_games = 0
print("Let's play the game of rock, Paper, Scissors.")
while play_again == 'y' or play_again == 'Y':
        computer_choice=process_computer_choice()
        player_choice=process_player_choice()

        if computer_choice == 1: 
            print('the computer chooses rock.')
        elif computer_choice == 2: 
            print('the computer chooses paper.')
        else: 
            print('the computer chooses scissors.')
        #display player choice
        if player_choice == 1: 
            print('You choose rock.')
        elif player_choice == 2:
            print('You choose paper.')
        else: 
            print('You choose scissors.')

            result = determine_winner(player_choice, computer_choice)
if results == 'computer':
            number_of_computer_games += 1
elif result == 'player':
            number_of_player_games += 1
else: 
            number_of_tied_games += 1
    
play_again = input('Do you want to play again? (Enter y for yes): ')
print('There were', number_of_tied_games, 'tie games played.')
print('The computer won', number_of_computer_games, 'game(s).')
print('You won', number_of_player_games, 'game(s).')
def process_computer_choice():  
    choice1 = random.randint(1, 3)


def process_player_choice():
        print('What is your choice? Enter 1 for rock, 2 for paper, or 3 for scissors: ',)
        choice2 = int(input())
        while choice2 != 1 and choice2 !=2 and choice2 != 3:
            print('ERROR: the choice can only be 1, 2 or 3.')
            choice2 = int(input("Please enter a correct choice:"))
        return choice2

def determine_winner(player_choice, computer_choice):
        if coputer_choice == 1:
            if player_choice == 2:
                print('Paper covers rock. You wins!')
                winner = 'player'
        elif player_choice == 3:
             print('Rock crushes scissors. The computer wins!')
             winner = 'computer'
        else: 
             print('The game is tied. Try again.')
             winner = 'tied'
        if computer_choice == 2:
            if player_choice == 1:
                  print('Paper covers rock. The computer wins!')
                  winner = 'computer'
        elif player_choice == 3:
                print(' Scissors cuts paper.You win!')
                winner = 'player'
        else: 
                print('The game is tied. Try again.')
                winner = 'tied'
        if computer_choice == 3:
            if player_choice == 1:
                print('Rock smashes scissors. You win!')
                winner = 'player'
        elif player_choice == 2:
                print('Scissors cuts paper. The computer wins!')
                winner = 'computer'
        else: 
                print('The game is tied. Try again.')
                winner = 'tied'
        return winner
main()

Answer 1

play_again = 'y'    # <- here's the issue
number_of_tied_games = 0
number_of_player_games = 0
number_of_computer_games = 0
print("Let's play the game of rock, Paper, Scissors.")
while play_again == 'y' or play_again == 'Y':    # <-and here

You have to understand that a computer program goes top-down. Meaning that if you put this particullar code outside of main() (or any function in general) this happens:

Essentially you assign the variable play_again the value 'y' and then the computer keeps on checking if the play_again is still y, which it is. You can think of it as the computer completely ignoring the function until it's "called", meaning you do the thing you did at the end of the file "main()".