如何在Emacs Lisp中用字符串中的反斜杠替换正斜杠？

Question

I would like to replace forward slaches to backslashes in emacs lisp. If I use this :

(replace-regexp-in-string "\/" "\\" path))

I get an error.

(error "Invalid use of `\\' in replacement text")

So how to represent the backslash in the second regexp?

Answer 1

What you are seeing in "C:\\\\foo\\\\bar" is the textual representation of the string "C:\\foo\\bar" , with escaped backslashes for further processing.

For example, if you make a string of length 1 with the backslash character:

(make-string 1 ?\\)

you get the following response (eg in the minibuffer, when you evaluate the above with Cx Ce):

"\\"

Another way to get what you want is to switch the "literal" flag on:

(replace-regexp-in-string "/" "\\" path t t)

By the way, you don't need to escape the slash.

Answer 2

Does it need to be double-escaped?

ie

(replace-regexp-in-string "\/" "\\\\" path)

Answer 3

Try using the regexp-quote function, like so:

(replace-regexp-in-string "/" (regexp-quote "\\\\") "this/is//a/test")

regexp-quote's documentation reads

(regexp-quote string) Return a regexp string which matches exactly string and nothing else.

Answer 4

Don't use emacs but I guess it supports some form of specifying unicode via \\x

eg maybe this works

(replace-regexp-in-string "\x005c" "\x005f" path))

or

(replace-regexp-in-string "\u005c" "\u005f" path))