如何根据javascript中的条件显示数字列表

Question

I would like to know how to get the list of numbers based on two condition

• number should be divisible by 3
• number should not end with 3 How to implement the list within 50 numbers in javascript

Expected Output

6,9,12,15...45

My attempt

 function getNumbers() { var result = []; for (var i = 0; i < 50; i++) { if (i % 2 == 0) { return } else { result.push(i); return result.toString() } } } console.log(getNumbers())

Answer 1

This seems to work to specs - your specs says it should start at 6 and not at 1

 const numbers = [...Array(50).keys()]. filter(num => num !== 0 && num%3 === 0 && !String(num).endsWith("3")) console.log(numbers)

NOTE: You can change [...Array(50).keys()] to [...Array(50).keys()].slice(1) if you want to avoid the test for 0

Answer 2

You can do that with a check if the modulo of 3 is 0 and the modulo of 10 is not 3. If you want to beautify the code you can combine this answer with mplungjan answer, but i wanted to show a mathematical alternative of the !String(num).endsWith("3") method provided by mplungjan.

I started your iteration at 1 instead of 0 to avoid 0 being put into the array. I also corrected your return statements.

 function getNumbers() { var result = []; for (var i = 1; i < 50; i++) { if (i % 3 === 0 && i % 10 !== 3) { result.push(i); } } return result; } console.log(getNumbers())