将数据帧中整列的 timedelta 转换为浮点数

Question

I need to Convert timedelta to floating-point for every cell in a column of my data frame. Here is how you do it for single cell:

time_d = datetime_1 - datetime_2
number_of_days = float(time_d.days)

But when .days is applied to entire column this error appears:

AttributeError: 'Series' object has no attribute 'days'

I'd like the date difference to be in days to be used in future calculations.

Answer 1

使用Series.dt.days处理Series ：

df['column'] = df['column'].dt.days

Answer 2

尝试这个：

df['column'] = df['column'].map(lambda x: float(x.days))