[英]How can I change the group titles in a pandas grouped-by boxplot?
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
df = pd.DataFrame(np.random.randn(10, 3),
columns=['Col1', 'Col2', 'Col3'])
df['X'] = pd.Series(['A', 'A', 'A', 'A', 'A',
'B', 'B', 'B', 'B', 'B'])
df['Y'] = pd.Series(['A', 'B', 'A', 'B', 'A',
'B', 'A', 'B', 'A', 'B'])
boxplot = df.boxplot(column=['Col1', 'Col2'], by=['X', 'Y'])
plt.show()
I would like to change the two labels Col1
and Col2
, I have tried to pass the argument labels=['Left label','Right label']
(to the matplotlib core function https://matplotlib.org/api/_as_gen/matplotlib.pyplot.boxplot.html#matplotlib.pyplot.boxplot ) but with no luck:我想更改两个标签
Col1
和Col2
,我试图传递参数labels=['Left label','Right label']
(到 matplotlib 核心函数https://matplotlib.org/api/_as_gen/ matplotlib.pyplot.boxplot.html#matplotlib.pyplot.boxplot )但没有运气:
boxplot = df.boxplot(column=['Col1', 'Col2'], by=['X', 'Y'], labels=['Left label','Right label'])
gives me the error:给我错误:
ValueError: Dimensions of labels and X must be compatible
Try this, because boxplot here returns a NumPy array of axes, you can use each element of this NumPy array and set_title:试试这个,因为这里的 boxplot 返回一个 NumPy 轴数组,你可以使用这个 NumPy 数组的每个元素和 set_title:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
df = pd.DataFrame(np.random.randn(10, 3),
columns=['Col1', 'Col2', 'Col3'])
df['X'] = pd.Series(['A', 'A', 'A', 'A', 'A',
'B', 'B', 'B', 'B', 'B'])
df['Y'] = pd.Series(['A', 'B', 'A', 'B', 'A',
'B', 'A', 'B', 'A', 'B'])
ax = df.boxplot(column=['Col1', 'Col2'], by=['X', 'Y'])
ax[0].set_title('AAA')
ax[1].set_title('BBB')
plt.show()
You may wish to try:你不妨试试:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
df = pd.DataFrame(np.random.randn(10, 3),
columns=['Col1', 'Col2', 'Col3'])
df['X'] = pd.Series(['A', 'A', 'A', 'A', 'A',
'B', 'B', 'B', 'B', 'B'])
df['Y'] = pd.Series(['A', 'B', 'A', 'B', 'A',
'B', 'A', 'B', 'A', 'B'])
axes = df.boxplot(column=['Col1', 'Col2'], by=['X', 'Y'])
titles=['Left label','Right label']
for ax, title in zip(axes,titles):
ax.set_title(title)
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