'Counter' 对象没有属性 'count'

Question

There are two lists and I want to check how many of elements are duplicate. Assuming list one is l1 = ['a', 'b', 'c', 'd', 'e'] and list two is l2 = ['a', 'f', 'c', 'g'] . Since a and c are in both lists, therefore, the output should be 2 which means there are two elements that repeated in both lists. Below is my code and I want to count how many 2 are in counter. I am not sure how to count that.

l1 = ['a', 'b', 'c', 'd', 'e']
l2 = ['a', 'f', 'c', 'g']
from collections import Counter
    c1 = Counter(l1)
    c2 = Counter(l2)
    sum = c1+c2
    z=sum.count(2)

Answer 1

What you want is set.intersection (if there are no duplicates in each list):

l1 = ['a', 'b', 'c', 'd', 'e']
l2 = ['a', 'f', 'c', 'g']

print(len(set(l1).intersection(l2)))

Output:

2

Answer 2

Every time we use a counter it converts the lists into dict. So it is throwing the error. You can simply change the number of lists and run the following code to get the exact number of duplicate values.

# Duplicate elements in 2 lists
l1 = ['a', 'b', 'c', 'd', 'e']
l2 = ['a', 'f', 'c', 'g']# a,c are duplicate
from collections import Counter

c1 = Counter(l1)
c2 = Counter(l2)
sum = c1+c2
j = sum.values()
print(sum)
print(j)

v = 0
for i in j:
    if i>1:
        v = v+1

print("Duplicate in lists:", v)

Output:

Counter({'a': 2, 'c': 2, 'b': 1, 'd': 1, 'e': 1, 'f': 1, 'g': 1})
dict_values([2, 1, 2, 1, 1, 1, 1])
Duplicate in lists: 2