使用字符串和整数对列表进行排序。 只对 int Python 进行排序

Question

Having trouble sorting a list with str and int. I want my code to return only listing int in asd and excluding str.

def data(data_list):
   for i, n in enumerate(data_list):
      mn = min(range(i,len(data_list)), key=data_list.__getitem__)
      data_list[i], data_list[mn] = data_list[mn], n
    return data_list
data([8,11,10,9,4,3])
#returns this
[3, 4, 8, 9, 10, 11] # which is great but when the list includes str it does not run 
#trying to run this 
data([8,11,'b',9,4,'a'])
# want to return this 
[3, 4, 8, 9]

#Also my code is quite confusing. I am sure there is a simpler way

Answer 1

You can simply use the built-in sorted() function and filter out items that are not integers using a list comprehension like so:

>>> datastr = [8, 11, 'b', 9, 4, 'a']
>>> sorted([v for v in datastr if isinstance(v, int)])
[4, 8, 9, 11]

Answer 2

You can use isinstance(i, int) to check if a particular object is of type int.

def data(data_list):
  return sorted([o for o in data_list if isinstance(o, int)])

If any on the numbers are strings, you can deal with them using a helper function like below

def intHelper(o):
  if isinstance(o, int):
    return o
  elif isinstance(o, str):
    try:
      return int(o)
    except ValueError:
      return None
  
  return None

def data(data_list):
  return sorted([o for o in list(map(intHelper, data_list)) if o is not None])

Answer 3

data = ['5',4,3,2,1.1,'zero','-1','0.4'] sorted_data = [] for datum in data: try: if isinstance(datum,str): if '.' in datum: sorted_data.append(float(datum)) else: sorted_data.append(int(datum)) else: if isinstance(datum,int): sorted_data.append(int(datum)) else: sorted_data.append(float(datum)) except: pass sorted_data.sort() print(sorted_data)