[英]If first condition satisfies perform it, otherwise second condition in Oracle
I am trying to take Employee by status from table.我正在尝试从表中按状态获取员工。 I have 2 statuses, If an employee has A condition take that row, otherwise take P status row with maximum oper_day It looks like below:
我有 2 个状态,如果员工有A条件,则取该行,否则取P状态行,最大oper_day如下所示:
Table桌子
---------------------------------------------------
id | emp_code | name | status | oper_day |
--------------------------------------------------
1 | 164094 | John | P | 2020-10-02 |
2 | 164094 | John | P | 2020-10-09 |
3 | 164094 | John | A | 2020-10-10 |
4 | 145890 | Mike | P | 2020-10-05 |
My result should look like below我的结果应该如下所示
--------------------------------
id | emp_code | name | status | oper_day |
--------------------------------------------------
1 | 164094 | John | A | 2020-10-10 |
2 | 145890 | Mike | P | 2020-10-05 |
Any help is appreciated任何帮助表示赞赏
Using ROW_NUMBER
:使用
ROW_NUMBER
:
WITH cte AS (
SELECT t.*, ROW_NUMBER() OVER (PARTITION BY emp_code ORDER BY status, oper_day DESC) rn
FROM yourTable t
)
SELECT id, emp_code, name, status, oper_day
FROM cte
WHERE rn = 1;
The logic here is that should an employee have a status A
record, it would be assigned the first row number, since A
sorts before P
.这里的逻辑是,如果员工有状态
A
记录,它将被分配第一个行号,因为A
在P
之前排序。 Otherwise, a P
status record would be chosen.否则,将选择
P
状态记录。 We choose the more recent record per employee in case of multiple records.如果有多个记录,我们会为每个员工选择最近的记录。
You can use aggregation functions with KEEP( DENSE_RANK FIRST ORDER BY ... )
:您可以将聚合函数与
KEEP( DENSE_RANK FIRST ORDER BY ... )
:
SELECT MAX( id ) KEEP ( DENSE_RANK FIRST ORDER BY status ASC, oper_day DESC ) AS id,
emp_code,
MAX( name ),
MIN( status ) AS status,
MAX( oper_day ) KEEP ( DENSE_RANK FIRST ORDER BY status ) AS oper_day
FROM table_name
GROUP BY
emp_code
Which., for your sample data:其中,对于您的示例数据:
CREATE TABLE table_name ( id, emp_code, name, status, oper_day ) AS
SELECT 1, 164094, 'John', 'P', DATE '2020-10-02' FROM DUAL UNION ALL
SELECT 2, 164094, 'John', 'P', DATE '2020-10-09' FROM DUAL UNION ALL
SELECT 3, 164094, 'John', 'A', DATE '2020-10-10' FROM DUAL UNION ALL
SELECT 4, 145890, 'Mike', 'P', DATE '2020-10-05' FROM DUAL;
Outputs:输出:
\nID |身份证 | EMP_CODE |
EMP_CODE | MAX(NAME) |
MAX(姓名) | STATUS |
状态 | OPER_DAY
OPER_DAY \n-: |
-: | -------: |
-------: | :-------- |
:-------- | :----- |
:----- | :------------------
:------------------\n 4 |
4 | 145890 |
145890 | Mike |
迈克 | P |
P | 2020-10-05 00:00:00
2020-10-05 00:00:00\n 3 |
3 | 164094 |
164094 | John |
约翰 | A |
一个 | 2020-10-10 00:00:00
2020-10-10 00:00:00\n
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