[英]Error: 'for' loop declarations only in c99 mode
I am trying to compile this C code in my linux system (I am new to all of this) and I keep getting this error:我正在尝试在我的 linux 系统中编译此 C 代码(我对所有这些都不熟悉),但我不断收到此错误:
ForkCall.c: In function ‘main’:
ForkCall.c:70:1: error: ‘for’ loop initial declarations are only allowed in C99 mode
for (int i=1; i<=5; i++)
^
ForkCall.c:70:1: note: use option -std=c99 or -std=gnu99 to compile your code
I tried declaring int i before the for loop, but got this error:我尝试在 for 循环之前声明 int i ,但出现此错误:
ForkCall.c: In function ‘main’:
ForkCall.c:69:1: error: a label can only be part of a statement and a declaration is
not a statement
int i;
^
This is the code:这是代码:
#include <stdio.h>
#include <unistd.h>
#include <sys/types.h>
int main()
{
pid_t pid, pid2;
int n;
printf("Select a number [1-5]: ") ;
scanf("%d", &n);
printf("\n\n");
switch(n)
{
case 1:
fork();
printf("This is process %d\n", getpid());
break;
case 2:
fork(); fork();
printf("This is process %d\n", getpid());
break;
case 3:
fork(); fork(); fork();
printf("This is process %d\n", getpid());
break;
case 4:
if((pid=fork()) && (pid2 = fork())) {fork();}
if((pid=fork()) && (pid2 = fork())) {fork();}
if ((pid=fork()) && (pid2 = fork())) {fork();}
printf("This is process %d\n", getpid());
break;
case 5:
for (int i=1; i<=5; i++)
{
fork();
}
printf("This is process %d\n", getpid());
break;
default:
printf("Number not in range [1-5] !\n");
}
}
``
Either set the option of the compiler that allows to compile code as a C99 code (or C11, or C18).设置允许将代码编译为 C99 代码(或 C11 或 C18)的编译器选项。 Or rewrite this part of the code:
或者重写这部分代码:
case 5:
for (int i=1; i<=5; i++)
{
fork();
}
printf("This is process %d\n", getpid());
break;
the following way以下方式
case 5:
{
int i = 1;
for ( ; i<=5; i++)
{
fork();
}
printf("This is process %d\n", getpid());
break;
}
That is, enclose the compound statement in this code snippet in braces.也就是说,将此代码片段中的复合语句括在大括号中。 Then the label will not precede a declaration.
那么标签将不会出现在声明之前。
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