这个python if语句有什么问题？

Question

I was making a function in python and used the following code:

def multi(_conv, _pretty = False):
  result = []
  newResult = ""
  for a in range(len(_conv)):
    for i in range(len(data)):
      if (str(_conv[a]) == data[i][0]):
        result.append(data[i][1]

  if(bool(_pretty) == True):
    for i in range(len(result)):
      newResult += str(result[i])
      if(i != len(result) - 1):
        newResult += ", "
    return newResult

but for a reason that I cannot figure out, on the line if(bool(_pretty) == True): I am getting a syntax error on the colon. I have tried making sure that the spacing is correct, that there are no issues with parenthesis being open, and have also tried rewriting it to make sure I wasn't missing something, but nothing has worked. If somebody could help that would be great!

edit: Sorry! I did not realize that there was still an unclosed pair of parenthesis. That is my bad...

Answer 1

You're missing a ) in result.append(data[i][1] causing the interpreter to get a little confused.

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Other issues...

You can use for to iterate directly through the items in a list.

No parens are required on if conditions.

There's no need to cast _pretty nor compare it to True. It's enough that _pretty is a true value .

The result formatting can be done with join .

  for c in _conv:
    for d in data:
      if str(c) == d[0]:
        result.append(d[1])

  if _pretty:
    return ", ".join(result)